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2 years ago

2. Find the difference when -4n - 8 is subtracted from 2n + 5

Mathematics

1 answer:

Orlov [11]2 years ago

3 0

Answer:

-6n - 13

Step-by-step explanation:

(-4n - 8) - (2n + 5)

Subtract -4n and 2n.

Then Add 8 and 5.

-6n - 13

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Need help please !!!

blsea [12.9K]

Answer:

option C is the correct answer

Step-by-step explanation:

The trigonometric equation you are using has a general form

y = A* tan w*(x - r)

Where

A is the amplitude of the function

w is the frequency rad/s

r is the phase shift

In your case

A = -2

The frequency is

w = (2*pi)/period

period = pi/4

w = 8

r = -pi/2

y = -2* cos 8*(x + pi/2)

7 0

2 years ago

Use a percent proportion or equation to answer: 150% of what number is 24

Delvig [45]

Answer is 36

150 • 24= 3,600

3,600/100= 36

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2 years ago

What is the value of f-1(4)

scZoUnD [109]

Answer:

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3 years ago

Heres the revenue and expenses for the month. Calculate whether mia had a profite or loss

8_murik_8 [283]

Answer:

profit $450

Step-by-step explanation:

subtract 9000 (expenses) from the revenue (9450) to get $450 of profit

8 0

2 years ago

Read 2 more answers

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

8 0

3 years ago