All categories

3 years ago

HEEEELPPPP I WILL GIVE BRAINLIEST

Mathematics

1 answer:

Kamila [148]3 years ago

6 0

Answer:

Q1, Q2 and Q3 are all congruent.

Step-by-step explanation:

As quadrilaterals are drawn on a Cartesian graph, it is easy to see that Quadrilateral−1, Quadrilateral−2 and Quadrilateral−3 are all congruent, while Quadrilateral−4 is different.The sides of Quadrilateral−1, Quadrilateral−2 and Quadrilateral−3 can be found using Pythagoras theorem and are {2,2,√10,√2} units. Even corresponding angles as well as diagonals two are congruent in these three quadrilaterals.Naming them as Q1, Q2, Q3 and Q4 respectively, we can say that pair wise Q1≡Q2, Q2≡Q3 and Q1≡Q3

You might be interested in

Helppppppppp!!!!!!!!

Pavlova-9 [17]

Answer:

The answer is D

Step-by-step explanation:

4 0

3 years ago

Hi, I am taking PSAT and I am working on the math section. I need help with answering this math type of question. Please give th

ValentinkaMS [17]

By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)

<h3>How many more distance does the average race car travels than the average consumer car?</h3>

In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:

s' = (v' - v) · t

Where:

v' - Speed of the average race car, in miles per hour.
v - Speed of the average consumer car, in miles per hour.
t - Time, in hours.

Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:

s' = (210 - 120) · (30 / 3600)

s' = 3 / 4 mi

The distance surplus of the average race car is equal to 3 / 4 miles.

To learn more on uniform rectilinear motion: brainly.com/question/10153269

#SPJ1

4 0

11 months ago

Pick the description of a geometric object that best matches the real-world object:<br><br> tent

Elodia [21]

Answer:

Triangular Prism

Step-by-step explanation:

We are given the object 'Tent' and are required to find a 3D object resembling it.

Since, the object represents a tent. So, it must have two similar and parallel bases with parallelograms as sides.

Therefore, we get that the 3D object that resembles a tent is a 'Triangular Prism'.

A triangular prism has two similar triangular bases and three rectangular sides as shown in the figure below.

Hence, 'Triangular Prism' is the answer.

5 0

2 years ago

For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive term

elena55 [62]

Answer:

The no. of variations in sign is 3

Step-by-step explanation:

Variation in sign occurs when every single time a negative product is produced by a pair of consecutive terms.

Therefore, the determination of the number of changes in sign in the given sequence is must.

Therefore, we take the product of the pair of consecutive terms as:

$1\times (-3)$ = - 3, variation in sign

$(-3)\times 2$ = - 6, variation in sign

$2\times 5$ = 10, no sign variation

$5\times (- 4)$ = - 20, variation in sign

$- 4\times (-6)$ = 24, no sign variation

7 0

3 years ago

What’s the height of the can?

kondaur [170]

Answer:

5 inches

Step-by-step explanation:

The formula to find the surface area of a cylinder is A = 2πrh + 2πr²

Since we need the height we will need to solve for h

First we can subtract 2πr² from both sides to get A - 2πr² = 2πrh
Then we can divide both sides by 2πr to get $h=\frac{A-2\pi r^{2} }{2\pi r}$

Now we can plug in our known values and solve for h

Here we were given the diameter, d, however this formula is in terms of the radius, r.
The diameter is equivalent to double the radius, d = 2r
Therefore the radius is equivalent to half the diameter, $r=\frac{1}{2} d$
Plugging in d to solve for r we get $r=\frac{1}{2}(2)$ which simplifies to r = 1

The two variables for this equation we have no obtained, A = 12π and r = 1, so we can plug them into our equation to solve for the height

$h=\frac{12\pi -2\pi (1)^{2} }{2\pi (1)}=h=\frac{12\pi -2\pi }{2\pi }=\frac{10\pi }{2\pi } =5$
The height is 5 inches

4 0

3 years ago