Answer:
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Answer:
Step-by-step explanation:
The conjugate is found by changing the sign of the square root term.‡ (For this purpose, i = √-1.)
a) the sign of 3i is changed: 2 + 3i
b) the sign of sqrt(-5) is changed: 8 -sqrt(-5) = 8 -i√5
c) the sign of 2i is changed: 7 +2i
d) the sign of sqrt(7) is changed: 4 +√7
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‡ Actually, the conjugate of a binomial is formed by changing the sign <em>between</em> terms. The purpose is to allow the product of the binomial and its conjugate to be the difference of squares.
Conventionally, the conjugate of a complex number is the value with the sign of the imaginary part reversed. That is why (-2i+7)* = 7+2i.
Answer:
8
Step-by-step explanation:
2log(x)=log(64)
By logarithms properties

log(x²)=log(64)
When you have log or ln in both sites, you delete them and...
x²=64
![\sqrt[]{x^{2} } =\sqrt{64} \\x=8](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7Bx%5E%7B2%7D%20%7D%20%3D%5Csqrt%7B64%7D%20%5C%5Cx%3D8)
Numbers divisible by 5 from 2 to 50 is 10 and numbers divisible by 8 from 2 to 50 is 6 ,therefore 6+ 10 =16 making 16/50 =8/25
It is 16 because 3x16=48 and 4x16=64!