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erik [133]
3 years ago
14

$8,425 divided by $10.25 please show your work

Mathematics
1 answer:
noname [10]3 years ago
7 0
The answer is 821.95 

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An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
A line has a slope of zero Which of the following points could this line pass through
Rina8888 [55]

Answer:

B

Step-by-step explanation:

m(slope) = y2 - y1 / x2 - x1

-6 - - 6 / 7 - 3

= 0 / 4 = 0

3 0
3 years ago
The measure of an angle exceeds 3 times its supplement by 4. Find the measure of the angles.
Dafna11 [192]
X=3y+4, y=y
x+y=180, 3y+4+y=180, 4y+4=180
4y+4=180
4y=176
y=44
x=3(44)+4, x=132+4, x=136

(I am not a very good artist in this case:)

4 0
3 years ago
Determine the vertex of the quadratic function.
const2013 [10]

Answer:

B

Step-by-step explanation:

The vertex is the turning point of the quadratic function.

In this case it lies on the x- axis at (2, 0 ) → B

6 0
3 years ago
Read 2 more answers
What is the solutions of the equation 2 (x+2) ^2-4=28
JulsSmile [24]

Answer:

x = 2            x = -6

Step-by-step explanation:

2 (x+2) ^2-4=28

Add 4 to each side

2 (x+2) ^2-4+4=28+4

2 (x+2) ^2= 32

Divide by 2

2/2 (x+2) ^2=32/2

(x+2)^2 = 16

Take the square root of each side

sqrt((x+2)^2) =±sqrt( 16)

x+2 = ±4

Subtract 2 from each side

x+2-2 = -2±4

x = -2±4

x = -2+4      and x = -2-4

x = 2            x = -6

3 0
3 years ago
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