<h2>QUESTION:</h2>
Evaluate 2t2 - 18 + ( incomplete question )
<h2>SOLUTION:</h2>
▶️ 2t2 - 18
▶️ 2t × 2 - 18
▶️ 4t - 18
<h2>ANSWER:</h2>
4t - 18
Answer:
135.5ft
Step-by-step explanation:
THIS COMPLETE THE QUESTION
flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.
Let X be the length of the wire
Let y be the height of the pole
X= Y + 14
Y= X -14
We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)
Using Pythagoras theorem
X²= 60² + Y²
X² = 3600 + Y²
if we subsitute for Y we have
X² = 3600 + (X -14)²
X² = 3600 +X² -14X-14X+196
X²-X²+ 28X= 3600+196
28X= 3796
X= 3796/28
=135.5ft
hence length of the wire is 135.5ft
Answer:
Step-by-step explanation:
3x < 4 - 1 or x > 31/9
3x < 3 or x > 31/9
x < 1 or x > 31/9
Answer:
see below
Step-by-step explanation: 7 1 16 33
y = x² translated t the point (3, 2) y = 0 when x = 0
y = (x - 3)² moves the function three units to the right y = 0 when x = -3
y = (x-3)² + 2 moves the function up 2 units y = 2 when x = -3
y = (x-3)² + 2
y = x² - 6x + 9 + 2
y = x² - 6x +11
graph the equations x², (x-3)² + 2, and x² - 6x + 11 to verify (I did)