Write the standard equation for the circle 30. Center (2,7), r=4. 31. Center (-6,-8), that passes treough (0,0)
1 answer:
The standard equation of the circle is:
(x-h)^2+(y-k)^2=r^2 where (h,k) it the center of the circle and r is the radius...
so
30.
(x-2)^2+(y-7)^2=16
31.
We need to find the radius...(I'll just use the Pythagorean Theorem)
r^2=6^2+8^2
r^2=36+64
r^2=100 (so the radius is 10) and its center is (-6,-8) so
(x+6)^2+(y+8)^2=100
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Answer:
y=15/7x-4
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(11-(-4))/(7-0)
m=(11+4)/7
m=15/7
y-y1=m(x-x1)
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250-177=73
250x0.292=73
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