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IceJOKER [234]
3 years ago
13

A bucket contains 5 green tennis balls and 2 yellow tennis balls. Tony removes 2 tennis balls with replacement, from the bucket

shown. What is the probability that tony will choose a yellow tennis ball then a green tennis ball?
Mathematics
1 answer:
mario62 [17]3 years ago
4 0
The probability that he will choose a green tennis ball is 1/5. the probability that he will choose a yellow one is 1/2. Hope this helps

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kvv77 [185]

Answer:

80 m²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h (a + b)

where h is the perpendicular height between bases and a, b are the bases

Here h = 8, a = 14 and b = 6, thus

A = \frac{1}{2} × 8 × (14 + 6) = 4 × 20 = 80 m²

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Please Help me solve: 7/8 * 1/4<br> Please give your answer in simplest form, Thank You!
alukav5142 [94]
Make them the same demonatator so 7/8 times 2/8 which equals 14 over 8 for a mixed number of 1 6/8
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3 years ago
Solve for x x+14=5x-74​
vitfil [10]

Step-by-step explanation:

x - 5x = -74 - 14

-4x = -88

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8 0
3 years ago
Read 2 more answers
What is the answer please help
Ne4ueva [31]
180 degrees - 46 degrees
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8 0
2 years ago
A. Student GPAs: Bob’s z-score z = + 1.71 μ = 2.98 σ = 0.36 b. Weekly work hours: Sarah’s z-score z = + 1.18 μ = 21.6 σ = 7.1 c.
hjlf

Answer:

a) x = \mu +z*\sigma

And replacing we got:

x= 2.98 + 1.71*0.36 = 3.5956

b) x = \mu +z*\sigma

And replacing we got:

x= 21.6 + 1.18*7.1 = 29.978

c) x = \mu -z*\sigma

And replacing we got:

x= 150 - 1.35*40= 96

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable of interest for this case. We define the z score with the following formula:

z=\frac{x-\mu}{\sigma}

And for this case we know that z = 1.71, \mu = 2.98,\sigma = 0.36

If we solve for x from the z score formula we got:

x = \mu +z*\sigma

And replacing we got:

x= 2.98 + 1.71*0.36 = 3.5956

Part b

Let X the random variable of interest for this case. We define the z score with the following formula:

z=\frac{x-\mu}{\sigma}

And for this case we know that z = 1.18, \mu = 21.6,\sigma = 7.1

If we solve for x from the z score formula we got:

x = \mu +z*\sigma

And replacing we got:

x= 21.6 + 1.18*7.1 = 29.978

Part c

Let X the random variable of interest for this case. We define the z score with the following formula:

z=\frac{x-\mu}{\sigma}

And for this case we know that z = -1.35, \mu = 150,\sigma = 40

If we solve for x from the z score formula we got:

x = \mu -z*\sigma

And replacing we got:

x= 150 - 1.35*40= 96

5 0
2 years ago
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