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3 years ago

Identify the ordered pair that represents the vector from A(1,6) to B(2, -3) and the magnitude of AB-

Mathematics

1 answer:

marissa [1.9K]3 years ago

7 0

Vector & Magnitude is (1,-9) & 9.0854 respectively! Correct option is

D) (1, -9), 182 * 9.0854

Step-by-step explanation:

Here we have , We have to Identify the ordered pair that represents the vector from A(1,6) to B(2, -3) and the magnitude of AB . Let's find out:

Vector that represents from A(1,6) to B(2, -3) is given by :

⇒ $AB = (2-1) i + (-3-6)j$

⇒ $AB = i -9j$ or ,

⇒ $AB = (1,-9)$

Now , Magnitude of vector AB is :

⇒ $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

⇒ $\sqrt{(2-1)^2+(-3-6)^2}$

⇒ $\sqrt{(1)^2+(-9)^2}$

⇒ $\sqrt{82}$

⇒ $9.0854$

Therefore , Vector & Magnitude is (1,-9) & 9.0854 respectively! Correct option is D) (1, -9), 182 * 9.0854

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3 years ago

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According to scientific research, the probability that a person between the ages of 20 and 25 having high blood pressure, is onl

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<h2>The probability is ${\frac{83}{100} }^9 \times \frac{17}{100}$ + ${\frac{83}{100} }^8 \times {\frac{17}{100} }^2$ + ${\frac{83}{100} }^{10}$ .</h2>

Step-by-step explanation:

The probability of having high blood pressure is 17%.

We need to find the probability of 2 or fewer have high blood pressure.

Possibility 1: No one have high blood pressure.

The probability is ${\frac{100 -17}{100} }^{10} = {\frac{83}{100} }^{10}$ .

Possibility 2: Only one have high blood pressure.

The probability is ${\frac{83}{100} }^9 \times \frac{17}{100}$ .

Possibility 3: 2 among the 10 have the high blood pressure.

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Any of the possibilities can happen.

Hence, the required probability is ${\frac{83}{100} }^9 \times \frac{17}{100}$ + ${\frac{83}{100} }^8 \times {\frac{17}{100} }^2$ + ${\frac{83}{100} }^{10}$ .

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3 years ago

7p-(3p+4) = -2(2p-1)+10 Please answer!!!!!!!

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P=2
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