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podryga [215]
2 years ago
14

A snorkeler dives for a shell on a reef. After entering the water, the diver descends 11/3 feet in one second. Write an equation

that models the diver's position with respect to time.

Mathematics
2 answers:
True [87]2 years ago
5 0

x^2 -12x +11

We have the x intercepts so we can create the equation (x-1)(x-11).  Multiply it and you get your answer

stiv31 [10]2 years ago
4 0

Answer:

f(t)=t²-12t+11

Step-by-step explanation:

1) Having an attentive reading, we can see from the picture two coordinate points (1,0) and (11,0).

These points, has coordinates for x and y. Since those y-coordinates are zero, we have x-intercepts. Or the zeros of a function, in a quadratic function. Those intercepts minus x values equals zero. These x-intercepts we'll rename it as t, for time.

2) Plugging it in and writing it as groups:

f(t) = returns in feet

t= for time

f(t) =(t-1)(t-11)

Distributing the factors multiplying (t-1) times (t-11), goes:

f(t) =t²-12t+11

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nignag [31]

Answer:

we need to prove : for every integer n>1, the number n^{5}-n is a multiple of 5.

1) check divisibility for n=1, f(1)=(1)^{5}-1=0  (divisible)

2) Assume that f(k) is divisible by 5, f(k)=(k)^{5}-k

3) Induction,

f(k+1)=(k+1)^{5}-(k+1)

=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1

=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k

Now, f(k+1)-f(k)

f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)

f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k

f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k

Take out the common factor,

f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)      (divisible by 5)

add both the sides by f(k)

f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)

We have proved that difference between f(k+1) and f(k) is divisible by 5.

so, our assumption in step 2 is correct.

Since f(k) is divisible by 5, then f(k+1) must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number n^{5}-n is a multiple of 5.

3 0
2 years ago
How do I solve this? This is grade 9 math.
mafiozo [28]
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8 0
3 years ago
Graph the system of equations. <br> {<br> 8x+8y=64<br> 2x−2y=−4
siniylev [52]

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8 0
3 years ago
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HELPPP!!!!!!
Furkat [3]
<h3>Answer: Choice D)  31.2 miles</h3>

This value is approximate.

============================================================

Explanation:

Let's focus on the 48 degree angle. This angle combines with angle ABC to form a 90 degree angle. This means angle ABC is 90-48 = 42 degrees. Or in short we can say angle B = 42 when focusing on triangle ABC.

Now let's move to the 17 degree angle. Add on the 90 degree angle and we can see that angle CAB, aka angle A, is 17+90 = 107 degrees.

Based on those two interior angles, angle C must be...

A+B+C = 180

107+42+C = 180

149+C = 180

C = 180-149

C = 31

----------------

To sum things up so far, we have these known properties of triangle ABC

  • angle A = 107 degrees
  • side c = side AB = 24 miles
  • angle B = 42 degrees
  • angle C = 31 degrees

Let's use the law of sines to find side b, which is opposite angle B. This will find the length of side AC (which is the distance from the storm to station A).

b/sin(B) = c/sin(C)

b/sin(42) = 24/sin(31)

b = sin(42)*24/sin(31)

b = 31.1804803080182 which is approximate

b = 31.2 miles is the distance from the storm to station A

Make sure your calculator is in degree mode.

8 0
2 years ago
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