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Norma-Jean [14]
2 years ago
6

Quick need help solving the specified variable 50 POINTS!!!!!!!

Mathematics
1 answer:
sattari [20]2 years ago
4 0

Answer: T=\frac{A-P}{PR}

Step-by-step explanation:

Given the following formula provided in the exercise:

A=P+PRT

You can follow the steps  shown below in order to solve for the variable T:

 Step 1: You need to subtract P from both sides of the equation. Then:

A-(P)=P+PRT-(P)\\\\A-P=PRT

Step 2: Finally, you need to divide both sides of the equation by PR. Then you get:

\frac{A-P}{PR}=\frac{PRT}{PR}\\\\T=\frac{A-P}{PR}

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Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .
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y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11

The equation of the perpendicular bisector is y = -x + 11

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