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salantis [7]
3 years ago
13

How to graph a slope intercept equation

Mathematics
2 answers:
max2010maxim [7]3 years ago
4 0

Here's a picture explaining the steps:

Luden [163]3 years ago
3 0

Answer:

1    m is the slope (lesson on slope ) mnemonic : 'm' means 'move'

 2  b is the y -intercept ( lesson on the y-intercept ) mnemonic : 'b' means where the line begins.

Step-by-step explanation:

hope this helps

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Edith leaves her home at 11:50 am.
dexar [7]

Answer:

2:30 minutes her journey finish.

distance / speed = time

75 / 30 = 2.5 hours :

it means  2:20 pm they finish her journey

Step-by-step explanation:

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8 0
3 years ago
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Wat 1 +1 i stoopid need help now. NOW!NOW!NOW!NOW!NOW!NOW!
sineoko [7]
1 + 1 is 467. You’ll learn it in Gr. 12. Really advanced and hard to learn
7 0
3 years ago
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Please help with this
Elena L [17]

Here

radius( r) =12/2=6 in.

height(h)=13 in.

now,

volume of hemisphere(V1)=

\frac{2}{3} \pi \:  {r}^{3}  =  \frac{2}{3}\pi  {6}^{3}  = 144\pi \: cu. \: in.

volume of cylinder(V2)=

\pi {r}^{2} h = \pi \times  {6}^{2}  \times 13 = 468\pi \\

now total volume=V1+V2

=144Pi +468pi

=212pi

8 0
4 years ago
Write the point-slope form of the given line that passes through the points (0, 3) and (4,0). Identify (x, y) as the X-
motikmotik

Answer:

y-3= -3/4 -(x+0)

Step-by-step explanation:

y2-y1   3-0=  3

x2-x1   0-4= -4

slope is  - 3/4

y= mx=b

y = -3/4x + 3

6 0
3 years ago
This graph represents a quadratic function. What is the function’s equation written in factored form and in vertex form?
AnnZ [28]

Answer:

\textsf{Factored form}: \quad f(x)=2x(x-4)

\textsf{Vertex form}: \quad f(x)=2(x-2)^2-8

Step-by-step explanation:

<u>Factored form of a quadratic function</u>

f(x)=a(x-p)(x-q)

where:

  • p and q are the x-intercepts
  • a is some constant

Given x-intercepts:

  • (0, 0)
  • (4, 0)

Therefore:

\implies f(x)=a(x-0)(x-4)

\implies f(x)=ax(x-4)

To find a, substitute the given vertex (2, -8) into the equation and solve for a:

\implies 2a(2-4)=-8

\implies -4a=-8

\implies a=2

Therefore, the function's equation in factored form is:

f(x)=2x(x-4)

<u>Vertex form of a quadratic equation</u>

<u />f(x)=a(x-h)^2+k

where:

  • (h, k) is the vertex
  • a is some constant

Given:

  • vertex = (2, -8)

Therefore:

\implies f(x)=a(x-2)^2-8

To find the constant a, substitute one of the x-intercepts into the equation and solve for a:

\implies a(0-2)^2-8=0

\implies 4a-8=0

\implies a=2

Therefore, the function's equation in vertex form is:

f(x)=2(x-2)^2-8

4 0
2 years ago
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