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nikitadnepr [17]
3 years ago
10

Nia solved the equation -1.98 = 5.2v + 13.1. Her answer was v = -2.9. She is fairly confident about her answer, but wants to do

a quick check of her solution using estimation to make sure her answer is reasonable.
Which of the following shows a good check of her answer?

-2 = 5(-3) + 13
-3 = 5(-2) + 13
-1 = 5(-2) + 13
-2 = 5(-2) + 13
Mathematics
1 answer:
icang [17]3 years ago
4 0
Remember when you just said random stuff on all my questions to get points, Anyways it's A. because they found to those numbers
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How large a sample should be selected to provide a 95% confidence interval with a margin of error of 6? Assume that the populati
marshall27 [118]

Using the z-distribution, it is found that a sample of 171 should be selected.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

For this problem, the parameters are:

z = 1.96, \sigma = 40, M = 6

Hence we solve for n to find the needed sample size.

M = z\frac{\sigma}{\sqrt{n}}

6 = 1.96\frac{40}{\sqrt{n}}

6\sqrt{n} = 40 \times 1.96

\sqrt{n} = \frac{40 \times 1.96}{6}

(\sqrt{n})^2 = \left(\frac{40 \times 1.96}{6}\right)^2

n = 170.7.

Rounding up, a sample of 171 should be selected.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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2 years ago
I need help on this one too
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Answer:

C.. is the answer.........

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