A----------D----------C
AD = 2x + 6
DC = 4x - 7
the midpoint D splits AC into 2 equal parts....therefore, AD = DC
2x + 6 = 4x - 7
2x - 4x = -7 - 6
-2x = - 13
x = -13/-2
x = 6.5
DC = 4x - 7......4(6.5) - 7 = 19 <===
AD = 2x + 6.....2(6.5) + 6 = 19
Answer:
B
Step-by-step explanation:
When testing hypothesis to make a conclusion, you must find sufficient evident to reject the null hypothesis in favor of the alternative hypothesis. The null hypothesis must fail in order to accept the alternative. Failing to reject is not enough information. Since this is the case then options C and D are false statements and cannot be true. Both state that if you reject the null then the alternative is false or can't be supported. The opposite is true. Option A is also false since you cannot accept the null. You can only fail to reject it. If this is true then the alternative certainly cannot be accepted. Option B must be correct and the statement (thought not listed here) must be true.
A. This statement is false. A true statement is, "If you decide to accept the null hypothesis, then you can support the alternative hypothesis."
B. This statement is true.
C. This statement is false. A true statement is, "If you decide to reject the null hypothesis, then you can't support the alternative hypothesis."
D. This statement is false. A true statement is, "If you decide to reject the null hypothesis, then you can assume the alternative hypothesis is false."
Subtraction and division are from the principal operations of PEMDAS. PEMDAS stands for parentheses, exponents, multiply and divide, add and subtract and thats it! Hope this helps and remember to mark as brainliest!
250 * 0.20 = $50 sale
250 - 50 = $200
You will pay $200 after sale

<em><u>Solution:</u></em>
From given question,
Number of pounds Jake carry = 
Number of pounds his father carry is
times as much as jake
To find: Number of pounds Jake father can carry
<em><u>Convert the mixed fractions to improper fractions</u></em>
Multiply the whole number part by the fraction's denominator.
Add that to the numerator.
Then write the result on top of the denominator

<em><u>Then according to question,</u></em>

