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MissTica
4 years ago
13

The quotient of a number and 6 minus is 1

Mathematics
2 answers:
prohojiy [21]4 years ago
6 0

Answer:

let the number x

x=6-1

x=5

ryzh [129]4 years ago
3 0

Answer:

x=7 or x=-7 (think its 7)

Step-by-step explanation:

Trying to think on the top of my head. Don't sleep on it.

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find the perpendicular distance between (2,5) and the line 2x - y + 7 = 0 in a surd form with a rational denominator
Alona [7]
The\ distance\ between\ P(x_P;\ y_P)\ and\ the\ line\ Ax+By+C=0:\\\\d=\frac{|Ax_P+By_P+C|}{\sqrt{A^2+B^2}}\\===================================\\P(2;\ 5);\ 2x-y+7=0\\\\x_P=2;\ y_P=5;\ A=2;\ B=-1;\ C=7\\\\d=\frac{|2\times2-1\times5+7|}{\sqrt{2^2+(-1)^2}}=\frac{|4-5+7|}{\sqrt{4+1}}=\frac{|6|}{\sqrt5}\cdot\frac{\sqrt5}{\sqrt5}=\frac{6\sqrt5}{5}
7 0
4 years ago
Two fair dice are tossed, and the up face on each die is recorded. Find the probability of observing A: { A 3 appears on each of
Arturiano [62]

Answer: 0.0278

Step-by-step explanation:

On a fair dice , there are six numbers (1,2,3,4,5,6) written on each face of dice.

Thus, when we thrown two dice , the sample space for the possibilities of outcomes will become :

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

i.e. Total number of outcomes = 36

For event A: { 3 appears on each of two dice.}

The favorable outcome = (3,3)

Now, the required probability : P(A)=\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}

=\dfrac{1}{36}=0.0277777777778\approx0.0278

Hence, the required probability is 0.0278.

3 0
4 years ago
44 times 79 equals what
IrinaK [193]

Answer:

3476

Step-by-step explanation:

40x70=2800

40x9=+

            360

________

3160

4x70=280

4x9=36

3160+316=3476

7 0
3 years ago
What is the radical form of the expression?
yan [13]
Last option. You got it.
6 0
3 years ago
Read 2 more answers
Sketch the graph of a function f having the given characteristics.
WITCHER [35]
So...that's telling you:
Y=0 at x=0 and x=2
The graph is decreasing when X is less than 1
f'(x) can not equal 0 with the previous statement.... please give the correct statement... I would assume that is is f'(1)=0, so there would be a max at x=1
f(x) is increasing when x is greater than 1
and if f''(x) is always 0, the graph is always concave downward.
3 0
3 years ago
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