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Neko [114]
3 years ago
6

How do you find the number of possible choices for a 2 digit password that is greater than 19?

Mathematics
1 answer:
topjm [15]3 years ago
3 0
There probably is a formula to do this, but a simple way to find this one is to just think of all two digit numbers. That is 00-99. All you do is count the number of possible choices from 20-99. So there are 80 possible choices.
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What is a simple formula to solve a math sequence? Or a couple formulas if possible? Thanks!
-Dominant- [34]
2 normal types of sequences:

1. arythmetic sequences: each term is the same distance to the next term, example, 2,4,6,8, distance is 2

2. geometric sequences: the ratio of consecutive terms is the same, example: 2,4,8,16, ratio is 4:2=2:1, 2/1=2


the nth term is denoted by a_{n}
the first term is represented by a_{1}

for arythmetic sequences, the nth tem is
a_{n}=a_{1}(n-1)d where d=distance between each term

for geometric sequences the nth term is
[tex] a_{n}=a_{1}r^{n-1} where r=ratio betwen consecutive terms

7 0
3 years ago
Damon works 32 hours per week and earns $10.75 per hour.
balu736 [363]
B. Find the exact number of earnings
7 0
3 years ago
Relate the volume of the cubes to length of each edge V = 8 cm3
sergiy2304 [10]

Answer:

2cm, 2cm and 2cm

Step-by-step explanation:

\sqrt[3]{8} = 2

4 0
1 year ago
A square in the board below and a letter in the word ATTENTION is chosen at
kolezko [41]

Answer:

4 /15

Step-by-step explanation:

From the number cube :

Count of Numbers greater than 4 = 16

Sample space of number cube = 20

P(number greater than 4) = 16 / 20 = 4/5

Word : ATTENTION

Count of letters in attention = 9

Count of T's in attention = 3

P(choosing T) = 3 / 9 = 1/3

P(greater than 4, then T) = 4/5 * 1/3 = 4 /15

5 0
2 years ago
Selmas class making a care package to give to victims of a natural disaster.Selma packs one box in 5 minutes and has already pac
bixtya [17]

Each of them need to work 105 minutes more in order to have packed the same number of boxes.

<u><em>Explanation</em></u>

Suppose, they need to work for x minutes more in order to have packed the same number of boxes.

Selma packs one box in 5 minutes and Trudy packs one box in 7 minutes.

So, the number of boxes packed by Selma in that x minutes =\frac{x}{5} and the number of boxes packed by Trudy in x minutes =\frac{x}{7}

Given that, Selma and Trudy have already packed 12 and 18 boxes.

Now if <u>each of them packed the same number of boxes</u>, then the equation will be......

12+\frac{x}{5}=18+\frac{x}{7}\\ \\ \frac{x}{5}-\frac{x}{7}= 18-12\\ \\ \frac{7x-5x}{35}=6\\ \\ \frac{2x}{35}=6\\ \\ 2x= 210\\ \\ x= \frac{210}{2}=105

So, each of them need to work 105 minutes more in order to have packed the same number of boxes.

6 0
3 years ago
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