4 years ago

How do you find the number of possible choices for a 2 digit password that is greater than 19?

1 answer:

3 0

There probably is a formula to do this, but a simple way to find this one is to just think of all two digit numbers. That is 00-99. All you do is count the number of possible choices from 20-99. So there are 80 possible choices.

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Answer:

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If $\frac{CE}{CB} = \frac{DC}{AC}$ and m∠ECD = m∠BCA, then the triangles are similar by the SAS theorem.

$\frac{EC}{BC} = \frac{14}{21} = \frac{2}{3}$ $\frac{DC}{AC} = \frac{18}{27} = \frac{2}{3}$

So, $\frac{CE}{CB} = \frac{DC}{AC}$ and m∠ECD = m∠BCA because vertical angles are congruent

Therefore ΔECD is similar to ΔBCA by SAS theorem

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