It takes 2 seconds to reach a maximum height of 69 feet, and the range is [5, 69].
The equation is of the form
h(t) = -16t² + v₀t + h₀, where -16 is the gravitational constant, v₀ is the initial velocity, and h₀ is the initial height. Using the values from our problem, we have:
h(t) = -16t² + 64t + 5
To find the maximum height, we find the vertex. The first step in this is to find the axis of symmetry, which is given by -b/2a:
-64/2(-16) = -64/-32 = 2
This is our value for t, so it takes 2 seconds to reach the maximum. Substituting this into our function, we have
h(2) = -16(2²) + 64(2) + 5 = -64 + 128 + 5 = 64 + 5 = 69
This is the maximum height.
The range of heights goes from 5 to 69, inclusive, or [5, 69].
(1 + i)/(1 + 2i)
To simplify this, we need to multiply both sides by the conjugate.
(1 + i)(1 - 2i)
1 - 2i - i - 3i^2
Combine like terms.
3i^2 - 3i + 1
i^2 = -1
-3i - 2 is the simplified numerator.
(1 + 2i)(1 - 2i)
1 - 2i + 2i - 4i^2
1 - 4i^2
i^2 = -2
1 + 4
5
<h3><u>The simplified expression is ((-3i)/5) + ((-2)/5)</u></h3>
1 inch =25.4 millimeters
therefore to calculate the number of millimeters that are in 57 inches we proceed as follows;
(25.4)/1*57
=1447.8/1
=1447.8 millimeters
The answer is 1447.8 mm
Therefore we conclude that there are 1,447.8 millimeters in 57 inches.
Answer:
n=-7
Step-by-step explanation:
For this you can do the inverse of division which is division. So Divide -91 and 13. Which is -7.
