Answer:
2
Step-by-step explanation:
<u>Given AP where:</u>
<u>To find</u>
<u>Since</u>
- a₄ = a₁ + 3d
- a₂ = a₁ + d
- a₆ = a₁ + 5d
<u>Initial equations will change as:</u>
- a₁ + 3d = 2(a₁ + d) - 1 ⇒ a₁ + 3d = 2a₁ + 2d - 1 ⇒ a₁ = d + 1
- a₁ + 5d = 7 ⇒ a₁ = 7 - 5d
<u>Comparing the above:</u>
- d + 1 = 7 - 5d
- 6d = 6
- d = 1
<u>Then:</u>
- a₁ = d + 1 = 1 + 1 = 2
- a₁ = 2
The first term is 2
Answer:
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389 children and 224 adults were at the pool that day.
Step-by-step explanation:
Cost of one child ticket = $1.75
Cost of one adult ticket = $2.25
Total people = 613
Total receipts worth = $1184.75
Let,
Number of children = x
Number of adults = y
According to given statement;
x+y=613 Eqn 1
1.75x+2.25y=1184.75 Eqn 2
Multiplying Eqn 1 by 1.75

Subtracting Eqn 3 from Eqn 2

Dividing both sides by 0.50

Putting y=224 in Eqn 1

389 children and 224 adults were at the pool that day.
Keywords: linear equation, subtraction
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Answer:
The number of elephant ears that must be sold to maximize profit is 400.
Step-by-step explanation:
Given that,
The profit that a vendor makes per day is given by
P(x)= - 0.004x² +3.2 x -200
where x is number of elephant ears.
P(x)= - 0.004x² +3.2 x -200
Differentiating with respect to x
P'(x)= - 0.008x+3.2
Again differentiating with respect to x
P''(x) = -0.008
For maximum or minimum P'(x)=0
- 0.008x+3.2=0
⇒0.008x=3.2

⇒ x = 400

Since at x=400, P''(x)<0, the profit is maximize.
P(400) = -0.004×400²+3.2×400-200
=440
The number of elephant ears that must be sold to maximize profit is 400.