Simplifying h(x) gives
h(x) = (x² - 3x - 4) / (x + 2)
h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)
h(x) = ((x + 2)² - 7x - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)
h(x) = (x + 2) - 7 - 22/(x + 2)
h(x) = x - 5 - 22/(x + 2)
An oblique asymptote of h(x) is a linear function p(x) = ax + b such that

In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.
<span><span><span>Let the original number be "x".
(x-10)/4 = 2
x-10 = 8
x = 18 (original number of pieces of candy.)</span></span></span>
Answer:
18.1
<em>The thing You NEEDED to do</em>
<h3>
<u>Simplify</u> or <u>Evaluate</u> Your Answer</h3>
Let
x------> the first even integer
x+2---->the second even integer
x+3---->the third even integer
we know that
-----> equation that represent the situation
solve for x
Combine like terms in the left side


therefore
<u>the answer is the option B</u>

(√3 + 1)/8 the answer to the question