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qwelly [4]
3 years ago
10

-2 2/3 + (-9 4/5)= ?

Mathematics
1 answer:
Nataly [62]3 years ago
6 0

Answer:

<em>-</em><em>2</em><em>2</em><em> </em><em>/</em><em>3</em><em> </em><em>+</em><em> </em><em>(</em><em>-</em><em>9</em><em>4</em><em>/</em><em>5</em><em>)</em><em> </em>

<em>-</em><em>2</em><em>2</em><em>/</em><em>3</em><em> </em><em>+</em><em> </em><em>-</em><em>8</em><em>9</em><em>/</em><em>5</em>

Step-by-step explanation:

<em>-</em><em>1</em><em>1</em><em>0</em><em>/</em><em>1</em><em>5</em><em> </em><em>+</em><em> </em><em>-</em><em> </em><em>2</em><em>5</em><em>7</em><em>/</em><em>1</em><em>5</em>

<em>-</em><em>3</em><em>6</em><em>7</em><em>/</em><em>1</em><em>5</em>

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3x+7y=-6<br> 7x+3y=26<br> solve by elimenation
Artemon [7]
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Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)
Pani-rosa [81]

Answer:

ABCD is not a parallelogram

Step-by-step explanation:

Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)

We have to find the length of the sides of the parallelogram using the formula below

= √(x2 - x1)² + (y2 - y1)² when given vertices (x1, y1) and (x2, y2)

For side AB

A(-3,2) B(-3,3)

= √(-3 -(-3))² + (3 -2)²

= √0² + 1²

= √1

= 1 unit

For side BC

B(-3,3) C (5,-3)

= √(5 -(-3))² + (-3 -3)²

= √8² + -6²

= √64 + 36

= √100

= 10 units

For side CD

C (5,-3) D (-1.-5)

= √(-1 - 5)² + (-5 - (-3))²

= √-6² + -2²

= √36 + 4

= √40 units

For sides AD

A(-3,2) D (-1.-5)

= √(-1 - (-3))² + (-5 -2)²

= √(2² + -7²)

= √(4 + 49)

= √53 units

A parallelogram is a quadrilateral with it's opposite sides equal

From the above calculation

Side AB ≠ CD

BC ≠ AD

Therefore, ABCD is not a parallelogram

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3 years ago
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Answer

5 and 90

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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