<span>19095705.3333 is the answer
hope i helped!</span>
Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
Answer:
I think It is 7
Step-by-step explanation:
Once you remember the definition of a log, the answer to this question will literally fall out of your pencil.
First, ' Ln ' means 'natural log' ... logs to the base of ' e '.
Definition of the natural log of a number:
In order to get the number, what power do I have to raise ' e ' to ?
OK. What power do you have to raise ' e ' to in order to get 1/e² ?
Isn't 1/e² the same thing as e⁻² ?
So, in order to get 1/e² , you have to raise ' e ' to the -2 power .
In math-speak: Ln(1/e²) = <em><u>-2</u></em> .
4 / (1/4 - 5/2)
4 / (1/4 -10/4)
4 / (-9/4)
4 x (-4/9) = -16/9