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Alona [7]
3 years ago
11

Two mechanics worked on a car. The first mechanic charged $85 per hour and the second mechanic charged $80 per hour the mechanic

s worked for a combined Total of 20 hours and together they charged a total of $1675. How long did each mechanic work?
Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:

Correct answer: First x = 15 h and second y = 5 h

Step-by-step explanation:

To solve this problem we will form a system of two equations with two variables:

Let be the time of the first mechanic x  and of the second y

x + y = 20  ⇒ y = 20 - x

85 x + 80 y = 1675

85 x + 80 (20 - x) = 1675

85 x + 1600 - 80 x = 1675

5 x = 1675 - 1600

5 x = 75

x = 75 / 5 = 15 h

x = 15 h

y = 20 - 15 = 5 h

y = 5 h

God is with you!!!

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3 years ago
a solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned
Jlenok [28]

Question:

A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .

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(b) How much of excess will be left after one month (1 month = 30 days)

Answer:

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Step-by-step explanation:

Given

Excess = 6500kwh

Rate = 50kwh/day

Solving (a): E in terms of d

The Excess left (E) in d days is calculated using:

E = Excess - Rate * days

The expression uses minus because there's a reduction in the excess kwh on a daily basis.

Substitute values for Excess, Rate and days

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Solving (b); The value of E when d = 30.

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E = 6500 - 50 * 30

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E = 5000

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Answer:

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Step-by-step explanation:

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