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yulyashka [42]
3 years ago
5

What is the perimeter of a polygon abcd

Mathematics
2 answers:
Lelu [443]3 years ago
7 0

You need to elaborate more. what is each side marked with? What are the answers to pick from. ECT.

Montano1993 [528]3 years ago
4 0

Answer: 36 on Plato

Step-by-step explanation:

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Because of hiring a plumber, y, to work x hours on a repair project can be modeled using a linear function. the plumber charges
seraphim [82]

Answer:

The plumbers cost would be equal to the equation 80+45x=y with y being the total amount of money he made and x being how many hours he worked.

Step-by-step explanation:

In this equation to find the amount the plumber was paid all you need to do is plug in the amount of hours he worked for x.

If the plumber worked his maximum of 8 hours then the equation would change from 80+45x=y to 80+(45×8)=440.

So, if the plumber worked for 8 hours he would make $440.

4 0
3 years ago
Solve for x: 4 over x plus 4 over quantity x squared minus 9 equals 3 over quantity x minus 3
dezoksy [38]

Answer:

Step-by-step explanation:

4/x + 4/(x²-9) = 3/(x - 3) 

4 / x + 4 / [( x - 3) ( x + 3 )] = 3 / ( x - 3 )  / * x ( x - 3 ) ( x + 3 )

Restrictions : x ≠ 0,  x ≠ - 3 ,  x ≠ 3;

4 ( x + 3 ) ( x - 3 ) + 4 x = 3 x ( x + 3 )

4 ( x² - 9 ) + 4 x = 3 x² + 9 x

4 x² - 36 + 4 x - 3 x² - 9 x = 0

x² - 5 x - 36 = 0

x² - 9 x + 4 x - 36 = 0

x ( x - 9 ) + 4 ( x - 9 ) = 0

( x - 9 ) ( x + 4 ) = 0

x - 9 = 0,  or : x + 4 = 0

Answer:

x = 9,  x = - 4

4 0
3 years ago
Triangle JKY is the image of triangle GBP after it has been rotated 180° about the origin.
sashaice [31]
∠G would be congruent to ∠J
∠B would be congruent to ∠K 
∠P would be congruent to ∠Y

Hope this helps :)
5 0
3 years ago
Use the table to determine the degree of the power function.
valkas [14]

9514 1404 393

Answer:

  3

Step-by-step explanation:

The x-values in the table are evenly-spaced, so we can determine the degree of the function by looking at successive differences of the f(x) terms.

f(x): -23, -4, 3, 4, 5, 12, 31

first differences: 19, 7, 1, 1, 7, 19

second differences: -12, -6, 0, 6, 12

third differences: 6, 6, 6, 6

The third differences are constant, so the function values can be matched by a <em>third degree</em> polynomial.

_____

<em>Additional comment</em>

The first differences are found by subtracting the function value from the next one. Likewise, the second differences are found by subtracting each first-difference value from the next one. An so on for the third differences.

The level at which the differences are constant is the degree of the polynomial that will match the function values. (Compare this to what you know about an arithmetic sequence, where first differences are constant and the sequence is described by a linear (degree 1) equation.)

5 0
3 years ago
You are creating an open top box with a piece of cardboard that is 16 x 30“. What size of square should be cut out of each corne
Arada [10]

Answer:

\frac{10}{3} \ inches of square should be cut out of each corner to create a box with the largest volume.

Step-by-step explanation:

Given: Dimension of cardboard= 16 x 30“.

As per the dimension given, we know Lenght is 30 inches and width is 16 inches. Also the cardboard has 4 corners which should be cut out.

Lets assume the cut out size of each corner be "x".

∴ Size of cardboard after 4 corner will be cut out is:

Length (l)= 30-2x

Width (w)= 16-2x

Height (h)= x

Now, finding the volume of box after 4 corner been cut out.

Formula; Volume (v)= l\times w\times h

Volume(v)= (30-2x)\times (16-2x)\times x

Using distributive property of multiplication

⇒ Volume(v)= 4x^{3} -92x^{2} +480x

Next using differentiative method to find box largest volume, we will have \frac{dv}{dx}= 0

\frac{d (4x^{3} -92x^{2} +480x)}{dx} = \frac{dv}{dx}

Differentiating the value

⇒\frac{dv}{dx} = 12x^{2} -184x+480

taking out 12 as common in the equation and subtituting the value.

⇒ 0= 12(x^{2} -\frac{46x}{3} +40)

solving quadratic equation inside the parenthesis.

⇒12(x^{2} -12x-\frac{10x}{x} +40)=0

Dividing 12 on both side

⇒[x(x-12)-\frac{10}{3} (x-12)]= 0

We can again take common as (x-12).

⇒ x(x-12)[x-\frac{10}{3} ]=0

∴(x-\frac{10}{3} ) (x-12)= 0

We have two value for x, which is 12 and \frac{10}{3}

12 is invalid as, w= (16-2x)= 16-2\times 12

∴ 24 inches can not be cut out of 16 inches width.

Hence, the cut out size from cardboard is \frac{10}{3}\ inches

Now, subtituting the value of x to find volume of the box.

Volume(v)= (30-2x)\times (16-2x)\times x

⇒ Volume(v)= (30-2\times \frac{10}{3} )\times (16-2\times \frac{10}{3})\times \frac{10}{3}

⇒ Volume(v)= (30-\frac{20}{3} ) (16-\frac{20}{3}) (\frac{10}{3} )

∴  Volume(v)= 725.93 inches³

6 0
3 years ago
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