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Romashka-Z-Leto [24]
3 years ago
12

Evaluate the expression for the given value. 3x(x−2), when x=7

Mathematics
1 answer:
Alexeev081 [22]3 years ago
6 0

Answer:

105

Step-by-step explanation:

Substitute X for 7:      3(7)(7-2)

Simplify:                      21(5)

Multiply:                       105

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*HELP ASAP I CAN ONLY DO THIS ONE TIME OR ILL FAIL*
docker41 [41]

Answer:

A

Step-by-step explanation:

V= BxHxL divided by 2

6x9x21= 1,134

divided by 2 equals 567yd

7 0
3 years ago
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PLEASE HELP!!!<br> Find the common difference for the arithmetic sequence. -55, -50, -45, -40.....
Fed [463]

Answer:

5

Step-by-step explanation:

Just grap any two consecutive terms in the sequence. lets say -55 and -50

-50-(-55) = 5

you can check this by picking two other terms

7 0
2 years ago
Can someone please help me!!!
egoroff_w [7]
The correct answer is the first one(a): To get the system B,..., the first equation multiplied by 4...

Explanation:

1. Let us first multiple the first equation in System A with 4, we would get:
4(2x - y) = 4 * 3

=> 8x - 4y = 12 --- (A)

Now add the equation (A) and the second equation of System A:

8x  - 4y = 12
3x + 4y = 10
------------------
11x = 22 

Hence,
System B:
2x - y = 3
11x = 22

-i
5 0
3 years ago
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HELPP! Geometry volume practice
GarryVolchara [31]

Answer:

Step-by-step explanation:

the height is 80 m

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7 0
3 years ago
One study reports that 34​% of newly hired MBAs are confronted with unethical business practices during their first year of empl
MaRussiya [10]

Answer:

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

\hat p=0.28 estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

p_o=0.34 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:  

Null hypothesis:p=0.34  

Alternative hypothesis:p \neq 0.34  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

5 0
3 years ago
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