Y=-3x^2+18x-25 move constant to other side
y+25=-3x^2+18x make leading coefficient 1 by dividing every thing by -3
(y+25)/-3=x^2-6x halve the linear coefficient, square it, add it to both sides...ie (-6/2)^2=9, so add 9 to both sides
(y+25-27)/-3=x^2-6x+9 now the right side is a perfect square
(y-2)/-3=(x-3)^2 now multiply both sides by -3
y-2=-3(x-3)^2 add 2 to both sides
y=-3(x-3)^2+2
f(x)=-3(x-3)^2+2
So the vertex here is an absolute maximum for the parabola as anything squared and then multiplied by a negative will decrease the value of y.
So the absolute maximum for f(x) occurs at the vertex (3, 2)
Answer:
x=-9
Step-by-step explanation:
You first multiple 2 and 25 and 2 and 2x. Then the next line should be -9-3x>50+4x+4. After that you add 50 and
X=6 and 8 these are your zeroes
Step-by-step explanation:
The range is the difference between the highest and lowest values in a set of numbers. To find it, subtract the lowest number in the distribution from the highest.
we see that the visible 7 numbers have a range of 50-17 = 33.
that means that x has to make sure that the range really is 69.
so, we have indeed 2 choices : x can be the lowest value (with a difference of 69 to the highest value, 50), or x can be the highest value (with a difference of 69 to the lowest value, 17).
x as the lowest value :
x = 50 - 69 = -19
x as the highest value :
x = 17 + 69 = 86
You are using 7 in both
In the first on you just multiply 7 x 4=28
In the second if you factor out 1000
The problem looks like this
7 x 2 x (1000)
7 x 2 is like the 7 x 4
When you multiply by 10, 100, 1000 etc you just add that many zeroes to the right of the number
Here is what it looks like
7 x 2 is 14 then 1000 has 3 0's so add them to 14, 14000
