D. A cluster tells you where there is a concentration of data values.
By using the information you have, you can use make a proportion to solve this.
You burn 4 logs in 2 hours or 4/2. You are comparing this to your unknown number, x, over 8 hours. So it looks like this 4/2 = x/8. You read it as four logs in two hours is x logs in eight hours. To solve you cross multiply. You do 2 times x and 4 times eight. That would be 2x= 32. Your goal is getting x alone, so divide each side by 2. Your answer is x= 16 logs in eight hours. You can solve this different and maybe easier ways but this is the best way if you want to get used to going this in algebra. Hope that helps! :)
(8x^2+5x+3)+(-5x^6-2x^5+4x^2-2x)=
8x^2+5x+3-5x^6-2x^5+4x^2-2x=
-5x^6-2x^5+(8-4)x^2+(5-2)x+3=
-5x^6-2x^5+4x^2+3x+3
Answer: Option B. -5x^6-2x^5+4x^2+3x+3
Check the picture below.
let's recall that a kite is a quadrilateral, and thus is a polygon with 4 sides
sum of all interior angles in a polygon
180(n - 2) n = number of sides
so for a quadrilateral that'd be 180( 4 - 2 ) = 360, thus
![\bf 3b+70+50+3b=360\implies 6b+120=360\implies 6b=240 \\\\\\ b=\cfrac{240}{6}\implies b=40 \\\\[-0.35em] ~\dotfill\\\\ \overline{XY}=\overline{YZ}\implies 3a-5=a+11\implies 2a-5=11 \\\\\\ 2a=16\implies a=\cfrac{16}{2}\implies a=8](https://tex.z-dn.net/?f=%5Cbf%203b%2B70%2B50%2B3b%3D360%5Cimplies%206b%2B120%3D360%5Cimplies%206b%3D240%20%5C%5C%5C%5C%5C%5C%20b%3D%5Ccfrac%7B240%7D%7B6%7D%5Cimplies%20b%3D40%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Coverline%7BXY%7D%3D%5Coverline%7BYZ%7D%5Cimplies%203a-5%3Da%2B11%5Cimplies%202a-5%3D11%20%5C%5C%5C%5C%5C%5C%202a%3D16%5Cimplies%20a%3D%5Ccfrac%7B16%7D%7B2%7D%5Cimplies%20a%3D8)
The answer to this problem is x - 17.
