Ask question

Ask question

All categories

2 years ago

12

Ralph sold brownies for $0.66 a piece in order to earn money to buy baseball cards. If the cards cost $0.90 per pack, and if Ral

ph ..

1 answer:

denpristay [2]2 years ago

5 0

What is the rest of the question

You might be interested in

Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9

mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that $\mu = 20.5, \sigma = 0.9$

What percentage of full-term babies are between 19 and 21 inches long at birth?

The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then

X = 21

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 20.5}{0.9}$

$Z = 0.56$

$Z = 0.56$ has a p-value of 0.7123

X = 19

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{19 - 20.5}{0.9}$

$Z = -1.67$

$Z = -1.67$ has a p-value of 0.0475

0.7123 - 0.0475 = 0.6648

0.6648*100% = 66.48%

66.48% of full-term babies are between 19 and 21 inches long at birth

5 0

2 years ago

A hardware store owner is replenishing his stock of base paint for an upcoming home improvement sale. He conducted a survey to d

antiseptic1488 [7]

Solution:

Matte Satin Glossy Total

Homeowners 0.08 0.20 0.24 0.52

Contractors 0.04 0.26 0.18 0.48

Total 0.12 0.46 0.42 1

Approximately what percentage of contractors prefer the glossy finish?

Answer: Percentage of contractors who prefer the glossy finish is:

$\frac{0.18}{0.48}=0.375
$ or $37.5\%$

Therefore, the option D. 37.5% is correct

6 0

3 years ago

Read 2 more answers

If a game consists of picking a number from a bag of beans numbered 2, 2, 3, 4, and 5 and flipping a coin, which probabilities a

White raven [17]

Answer:

I say C. Because 2 shows up twice for the bag of beans

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Of the 30 cars in a parking lot, 12 are blue, 8 are red, 6 are white, and 4 are silver. In simplest form, what are the odds in f

Radda [10]

Answer:

Step-by-step explanation:

8+6=14

14/30 = 7/15

So the final answer is 7/15

pls thank me pls :(

3 0

2 years ago

What are the vertices of POR?

cupoosta [38]

Answer is (d) P, Q , R

Any triangle has 3 vertices , after which its name is justified

8 0

3 years ago