Question

hat is the probability of drawing a green jellybean, eating it, and then drawing another green jellybean?2. A bag of jelly beans contains 24 jellybeans of different colors. There are 6 blue, 5 yellow, 10 green, and 3 black jellybeans. What is the probability of drawing a green jellybean, eating it, and then drawing another green jellybean? (please show all work.)

Answer 1

The chances of getting a green jelly bean is 10 out of 24, if you eat it then the chances of pulling another green jelly bean would be 9 out of 23

Answer 2

Answer:  The answer is 16.30%.

Step-by-step explanation:  Given that there is a bag of jelly beans in which

Total number of jelly beans = 24,

number of blue jelly beans = 6,

number of yellow jelly beans = 5,

number of green jelly beans = 10

and

number of black jelly beans = 3.

According to the question, first we draw a green jelly bean, ate it, and then again draw another green jelly bean.

Therefore, the probability of doing so is given by

$p=\dfrac{10}{24}\times \dfrac{9}{23}=\dfrac{90}{552}=0.1630=16.30\%.$

Thus, the required probability is 16.30%.