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aleksandr82 [10.1K]
3 years ago
7

A swimmer swam the 50-meter freestyle in a time of 21 seconds. What was the speed to the nearest tenth of a meter per second?

Mathematics
2 answers:
Mila [183]3 years ago
5 0

The answer would be 2.4 meters per second. To find this, you would divide the 50 meters by 21 seconds. It equals 2.380952, and rounds to 2.4m/s.

iogann1982 [59]3 years ago
5 0

Answer:

2.4 meter per second

Step-by-step explanation:

A swimmer swam the 50-meter freestyle in a time of 21 seconds.

Since a swimmer swam in 21 seconds = 50 meters

To calculate his speed in 1 second we will divide the total distance by the total  time.

Therefore, he swam in 1 second =  \frac{50}{21}

                                                     = 2.380952 rounded to 2.4 meter/sec

The speed of the swimmer is 2.4 meter per second.

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The length of a rectangle is twice its width. if the perimeter is 72 meters, find the length and width of the rectangle
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width(w)= w

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