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enyata [817]
4 years ago
8

268∙12+268∙23+732∙35

Mathematics
2 answers:
PolarNik [594]4 years ago
5 0
35,000 because 268(12), 268(23), and 732(35) are each added together separately.
lyudmila [28]4 years ago
3 0

The question is asking us to add 268∙12+268∙23+732∙35

The decimal numbers are added to the decimal numbers ,the digit at hundredth place are 2,3,5 which on addition gives 10 .We write 0 at the bottom and 1 is carried to the tenths place .The digit at tenths place are 1,2,3 which on addition will give 6 to this 1 is added to give 7.The digit at unit place are 8,8,2 which on addition will give 18 .1 is carried to the tens place the digit at tens place are 6,6,3 which on addition will give 15 to this 1 which was carried is added to give 16.The 1 is carried to hundred place The numbers at hundred place are 2,2,7 which on addition gives us 11 to this 1 carried is added to give 12.

268.12

268.23

732∙35

-------------

1268.70

The numbers 268∙12+268∙23+732∙35 on addition will give 1268.70

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When P = 9, we could multiply 9 to (2n+ 3).

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18n + 27

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Answer:

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3 years ago
Bob and Marie like to go to a good steakhouse. Dinners are $14 to $16 dollars with soup or salad. A beverage is $1.25. Dessert i
34kurt
Let's find the total cost before the tax and tip.

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To continually increase the speed of computers, electrical engineers are working on ever-decreasing scales.The size of devices c
Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

The question says the diameters of 50 pillars were measured. However, only the measurements of 20 pillars were provided.

So, I will work with 20

Given

n = 20

62\ 74\ 92\ 86\ 92

106\ 118\ 68\ 75\ 101

93\ 98\ 69\ 80\ 87

101\ 77\ 96\ 90\ 97

Solving (a): Frequency distribution table

Using the given intervals:

(60,70]\ => 61 - 70

(70, 80] =>71 - 80

(80,901]\ =>81 - 90

(90,100] =>91 - 100

(100, 110] =>101 - 110

(110,120] => 111 - 120

The table is as follows:

\begin{array}{ccc}{Interval} & {Class\ Mark (x)} & {Frequency (f)} & {61-70} & {65.5} & {3} \ \\ {71-80} & {75.5} & {3} & {81-90} & {85.5} & {3} & {91-100} & {95.5} & {7} & {101-110} & {105.5} & {3}  & {111-120} & {115.5} & {1} \ \end{array}

Total \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 20

The class mark is the average of the class interval

For instance: The class mark of 61 - 70 is:

x = \frac{1}{2}(61 + 70) = \frac{1}{2} * 131 = 65.5

<em>This is applied to other intervals</em>

Solving (b): The histogram

<em>See attachment for histogram</em>

The frequency is plotted on the y-axis while the class interval, on the x-axis.

7 0
3 years ago
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