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JulsSmile [24]
2 years ago
15

Hi would you be able to help me ignore my work

Mathematics
1 answer:
Ulleksa [173]2 years ago
5 0

Solution:

Given the system;

\begin{gathered} 4x+6y=32.............equation1 \\  \\ 3x-6y=3..............equation2 \end{gathered}

Add equation1 to equation2, we have;

\begin{gathered} 4x+3x+6y-6y=32+3 \\  \\ 7x=35 \\  \\ \frac{7x}{7}=\frac{35}{7} \\  \\ x=5 \end{gathered}

Substitute x = 5 in equation2;

\begin{gathered} 3x-6y=3 \\  \\ 3(5)-6y=3 \\  \\ 15-6y=3 \\  \\ 6y=15-3 \\  \\ 6y=12 \\  \\ y=2 \end{gathered}

ANSWER:

x=5,y=2

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kow [346]

Answer:

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