The system of equations to find the cost of one adult ticket, a, and the cost of one child ticket, c are Roy's; 6a+2c=66 Elisa's 5a+4c=62.
<h3>What is a system of equations?</h3>
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
Let's consider adults tickets be a and child tickets be c
so
Roy's purchase
6a+2c=66------1
Elisa's purchase
5a+4c=62-------2
Hence, the system of equations
6a+2c=66------1
5a+4c=62-------2
solving simultaneously
6a+2c=66
5a+4c=62
Also,
12a+4c=132
-5a+4c=62
7a=70
a=$10
put a=70 in 1
6(10)+2c=66
60+2c=66
2c=66-60
2c=6
c=$3
Learn more about equations here;
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The answer is <span>f(x) = 2x2 + 3x – 3
</span>
f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term
<u>We are looking for a = 2, c = -3</u>
Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.
In the function: <span>f(x) = –3x2 – 3x + 2
</span>a = -3
c = 2
In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3
Orange is 9.
so 9/(7+4+9 ) times 100.
the answer is 45%
Answer:
adjust the equation so the line passes through the points
