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3 years ago

I Need Help ASAP! 3:39 pm est answer as soon as you can!!!!

Mathematics

1 answer:

Firdavs [7]3 years ago

3 0

Uh oh it's due now I guess...

You might be interested in

Ravi can type 6 words in 4 seconds. How many words can he type in 10 seconds?

barxatty [35]

Divide 6 words by 4 seconds to find the rate of words per second.

6/4 = 1.5 words per second.

Multiply 1.5 by 10 seconds to obtain the answer:

15 words in 10 seconds.

3 0

3 years ago

Evaluate f(-12) given f(x) = -21x - 12

frozen [14]

Answer:

The answer for the given function is f( -12 ) = 240.

Step-by-step explanation:

Given:

$f(x)=-21x-12$

To Find :

F ( -12 ) = ?

Solution:

Function:

A function is like a machine that gives an output for a given input.
A function has an independent variable which is called the input of the function.
The output for a given input is called the dependent variable.

For Example

f ( x ) = x + 3

x = independent variable

f ( x ) = Output for a given input

Here we have

$f(x)=-21x-12\\Put\ x=-21\\\therefore f(-12) = -21\times -12 - 12\\\therefore f(-12) = 252 - 12\\\therefore f(-12) = 240$

Therefore f(-12) = 240

8 0

3 years ago

Read 2 more answers

Using the Babylonian method find √600 ???????????? √235.<br><br> how?

podryga [215]

Answer:

With the Babylonian method $\sqrt{600} \approx 24.494897$ and $\sqrt{235} \approx 15.329709$ .

Step-by-step explanation:

To find the square root of 600, do the following:

1. Make an initial guess: Because $\sqrt{576}=24$ and $\sqrt{625} =25$ you can start with $x_{0}=24$ as your initial guess.

2. Apply the formula:

$x_{1}=\frac{(x_{0}+\frac{x}{x_{0}})}{2}$ where $x=600$

$x_{1}=\frac{(24+\frac{600}{24})}{2}\\x_{1}=24.5$

The number $x_{1}$ is a better approximation to $\sqrt{600}$

3. Iterate until convergence:

For this apply the formula:

$x_{n+1}=\frac{(x_{n}+\frac{x}{x_{n}})}{2}$

Convergence is achieved when the digits of $x_{n+1}$ and $x_{n}$ agree to as many decimal places as you desire.

$x_{2}=\frac{(x_{1}+\frac{x}{x_{1}})}{2}\\x_{2}=\frac{(24.5+\frac{600}{24.5})}{2}\\x_{2}=24.494897$

$x_{3}=\frac{(x_{2}+\frac{x}{x_{2}})}{2}\\x_{3}=\frac{(24.494897+\frac{600}{24.494897})}{2}\\x_{3}=24.494897\\$

Because $x_{2}$ and $x_{3}$ agree to six decimal places. we can say that an estimate for $\sqrt{600} \approx 24.494897$ .

You can compare with the value that WolframAlpha gives you which is $\sqrt{600} \approx 24.49489742$ you can see that it agrees to six decimal places.

To find the square root of 235, do the following:

1. Make an initial guess: Because $\sqrt{225}=15$ and $\sqrt{256} =16$ you can start with $x_{0}=15$ as your initial guess.

2. Apply the formula:

$x_{1}=\frac{(x_{0}+\frac{x}{x_{0}})}{2}$ where $x=235$

$x_{1}=\frac{(15+\frac{235}{15})}{2}\\x_{1}=\frac{46}{3}$

3. Iterate until convergence:

Apply the formula:

$x_{n+1}=\frac{(x_{n}+\frac{x}{x_{n}})}{2}$

$x_{2}=\frac{(x_{1}+\frac{235}{x_{1}})}{2}\\x_{2}=\frac{(\frac{46}{3}+\frac{235}{\frac{46}{3}})}{2} \\x_{2}=15.329710$

$x_{3}=\frac{(x_{2}+\frac{235}{x_{2}})}{2}\\x_{3}=\frac{(15.329710+\frac{235}{15.329710})}{2} \\x_{3}=15.329709$

$x_{4}=\frac{(x_{3}+\frac{235}{x_{3}})}{2}\\x_{4}=\frac{(15.329709+\frac{235}{15.329709})}{2} \\x_{3}=15.329709$

Because $x_{3}$ and $x_{4}$ agree to six decimal places. We can say that an estimate for $\sqrt{235} \approx 15.329709$ .

WolframAlpha gives you $\sqrt{235} \approx 15.329709716$

4 0

4 years ago

Jackie is making flower arrangements. She has 2 roses and 4 daisies. If Jackie wants to make all the arrangements identical and

Alenkasestr [34]

Let's explore possible case scenarios.

---------------------

Case A) Each person gets a rose and a daisy (2 flowers per person)

In this case, Jackie can make 2 such arrangements because she has 2 roses. We have 2 left over daisies.

---------------------

Case B) Each person gets a rose only (1 flower per person)

Only two arrangements are possible for the same reason as case A. In this situation, we have 4 left over daisies.

----------------------

Case C) Each person gets a daisy only (1 flower per person)

We have 4 arrangements possible because we have 4 daisies. The left over flowers are the 2 roses.

-----------------------

Case D) Each person gets 2 roses

Only one such arrangement is possible, so this only applies to one person really. You can say that 2/2 = 1. We have 4 left over daisies in this case.

-----------------------

Case E) Each person gets 2 daisies

Since 4/2 = 2, this means we can make 2 arrangements. There are 2 left over roses.

------------------------

Case F) Each person gets 2 daisies and 1 rose

We can see that 4/2 = 2 and 2/2 = 1, meaning that we can make at most 2 arrangements here. There are no leftovers. In contrast, the other cases do have leftovers of some kind.

------------------------

In short, you can do trial and error to see which case works to fit the conditions your teacher set. Case F is what we go for to have each flower bouquet consist of 2 daisies and 1 rose. We'll get 2 bouquets possible. Notice how cases A through E have at least one left over flower (either of one kind or both types), while case F has no leftovers.

3 0

4 years ago

Is the expression 9(−4x−3) equivalent to the expression −36x−27.?

LekaFEV [45]

Answer:

No they are not equivilant. −36x−27 = 972 & 9(−4x−3) = 108.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers