Answer:
Part 1)
-------> 
Part 2)
--------> 
Part 3)
------> 
Part 4)
------> 
Step-by-step explanation:
Part 1) we have

To calculate the division problem convert the decimal number to fraction number
so

Remember that
Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

Simplify
Divide by 22 both numerator and denominator

Part 2) we have

To calculate the division problem convert the mixed number to an improper fraction

so

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

Convert to mixed number

Part 3) we have

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

Simplify
Divide by 5 both numerator and denominator

Part 4) we have

To calculate the division problem convert the mixed number to an improper fraction

so

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

Answer:
First of all, it is better to note that x2 is not equal to x² .In mathematics x2 is equal to 2nd x or 2x i.e. 2 times x=2*x=x*2.
I don't know what this question means ! But if it means to just confine x2 and -6x in a square or to make them part of a square then it could be done as follows.
Assume x2 as x² as per your needs as case may be.
Now use the identity
(a² - 2a×b + b²) =(a - b )²
Here , in LHS
a appears twice as in a² and in 2a×b.
So for given expression (x2 – 6x = 5) or (x² – 6x = 5) or (x² - 6x -5 =0)
Assume x=a
Then,
6x =2*x*3 =2*a*b
=> 3 = b
Thus
(x² - 6x -5 =0)
=> x² - 2*x*3 + 3² -3² -5 =0
=> ( x² - 2*x*3 + 3² ) - 3² -5 =0
=> (x - 3)² - 3² = 5
=> (x - 3)² = 5 + 3²
=> (x - 3)² = 5 + 9 = 14 = ( ±√(14) )²
Now comparing
(x² – 6x = 5) and (x - 3)² = 5 + 9,
it can be said that number 9 should be added to both sides of (x² – 6x = 5) or (x² – 6x) = ( 5 ) to make ( x² ) and (-6x ) as the constituting parts of the square (x-3)² .
I hope it helps.
Thank you for patiently reading it.