Long leg = 8 → opposite
short leg = 6 → adjacent
hypotenuse = ?
8² + 6² = c²
64 + 36 = c²
100 = c²
√100 = √c²
10 = c
sin ∠BOC = opposite / hypotenuse
sin ∠BOC = 8 / 10
sin ∠BOC = 0.80
tan ∠BOC = opposite / adjacent
tan ∠BOC = 8 / 6
tan ∠BOC = 1.33
Answer:
2x+1
Step-by-step explanation:
that's a hard question
we know that g(x)= x-3
so f(g(x))= f(x-3)
we put it in the equation :
f(x-3)= 2(x-3) +7 = 2x-6+7 = 2x +1
7 to 9 I believe if you take 4 and 7 and make them more it schools be that
This should help 10-1=9 9÷3=3 x=3
They are the same slope
they are negative inversees (they multily to get -1)
2
-1/2
use the square viewer (on TI)
The relationship between the slopes of two lines that are parallel is they are the same.
The relationship between the slopes of two lines that are perpendicular is they are negative inverses of each other (they multiply to -1).
A line that is parallel to a line whose slope is 2 has slope 2.
A line that is perpendicular to a line whose slope is 2 has slope -1/2.
What must be done to make the graphs of two perpendicular lines appear
to intersect at right angles when they are graphed using a graphing
utility?
