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3 years ago

Please answer this question only if you know it! 20 points and brainliest!

Mathematics

1 answer:

iren [92.7K]3 years ago

7 0

Answer:

They can split up groups of 20 for 12.5 tests to go on

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What is the distance between (0, 0) and (-7, -3)? Round your answer to the nearest tenth.

lyudmila [28]

Answer:

Distance = -7.6

Step-by-step explanation:

Using Distance Formula, √((x2-x1)^2 + (y2-y1)^2)

√((-7 - 0))^2 + (-3 - 0)^2) = 7.6

7 0

2 years ago

Suppose a projectile is fired from a cannon with velocity v0 and angle of elevation θ. The horizontal distance Rθ it travels (in

jolli1 [7]

Answer:

0.25 rad to the nearest hundredth radian

Step-by-step explanation:

Here is the complete question

Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.

R(θ) = v₀²sin2θ/32

If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?

Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.

(θ)= ?rad

Solution

R(θ) = v₀²sin2θ/32

If v₀ = 80 ft/s and R(θ) = 95 ft

θ = [sin⁻¹(32R(θ)/v₀²)]/2

= [sin⁻¹(32 × 95/80²)]/2

= [sin⁻¹(3040/6400)]/2

= [sin⁻¹(0.475)]/2

= 28.36°/2

= 14.18°

Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad

= 0.25 rad to the nearest hundredth radian

3 0

3 years ago

A tractor trailer's maximum load is 32,000 pounds. If it is already carrying a forklift that weighs 8,200 pounds, how many 250-p

mina [271]

32000-8200=23800pounds
23800/250=95

8 0

3 years ago

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

3 years ago

Please explain number 10 in a step by step process.

Aleonysh [2.5K]

Good evening ,

______________

Answer:

a=3

___________________

Step-by-step explanation:

Look at the photo below for the answer.

3 0

3 years ago

Read 2 more answers