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Leviafan [203]
3 years ago
9

You deposit $365$365 into a savings account. After one year, the amount in the account is $428$428. Which expression describes t

he percent of increase in the account balance?
Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0

Answer: There is 17.26% percent of increase in the account balance.

Step-by-step explanation:

Since we have given that

Amount deposited in saving account = $365

After one year,

Amount in saving account = $428

There is increase of

\$428-\$365\\\\=\$63

Rate of increase in the account balance is given by

\frac{63}{365}\times 100\\\\=17.26\%

Hence,there is 17.26% percent of increase in the account balance.

german3 years ago
6 0
Its approxamately 17.25%
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MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
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and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
2 years ago
Find the value of x<br> A.)25<br> B.)140<br> C.)5<br> D.)1
Vlada [557]

Answer:

25 = x

Step-by-step explanation:

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5x+15 = 6x -10

Subtract 5x from each side

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Add 10 to each side

15+10 = x-10+10

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Solving both of these we get:

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6 0
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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