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ss7ja [257]
3 years ago
5

Which option shows 18 divided by 15 as a fraction or mixed number

Mathematics
1 answer:
frutty [35]3 years ago
6 0
\dfrac{18}{15} =  1\dfrac{18-15}{15} =  1\dfrac{3}{15}
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Is this a true, is everything correct and how would you graph it.
Mashutka [201]

Answer:

Step-by-step explanation:

-x -6 ≤ 2 -(3x -4)

-x -6 ≤ 2 -3x + 4

-x ≤ -3x +12

2x ≤ 12

x ≤ 6

You would graph this on a number line with a solid dot on 6. Shade to the left.

3 0
4 years ago
Find all solutions to the equation
tresset_1 [31]

Answer:

0,1,2,3,4,5,6.......19,20

Step-by-step explanation:

in this interval 0 is included and 21 is not included. So starting from 0 up to 20, all are the solutions

5 0
3 years ago
The number on two consecutively numbered gym lockers have a sum of159. what are the locker numbers. Use comma to separate the an
svlad2 [7]
The answer is 79 and 80.

x - the number of the first locker
x + 1 - the number of the consecutive locker
Their sum is 159.

x + x + 1 = 159
2x + 1 = 159
2x = 159 - 1
2x = 158
x = 158 / 2
x = 79


x - the number of the first locker:                      x = 79
x + 1 - the number of the consecutive locker    x + 1 = 79 + 1 = 80
3 0
4 years ago
A mechanic buys $14.56 worth of parts from a supplier. If he pays for the parts with a $20 bill, how much change will he receive
balu736 [363]

This is a basic subtraction problem :-).

You will subtract how much money the mechanic gives to the supplier; which in this case will be $20, by the total amount of the parts which is $14.56.

20-14.56 = 5.44

Therefore, he will receive $5.44 in change for the transaction.

7 0
3 years ago
Read 2 more answers
what is the probability that a number selected at random from the set {2,3,7,12,15,22,72,108} will be divisible by both 2 and 3?
evablogger [386]
First, look at how many numbers are divisible by 2 and 3. 
12,72, and 108 and are all divisible by both 2 and 3. That makes 3 out of 8 numbers.
Depending on what form you have to put the probability, that makes it 3:8, 3 out of 8, or 37.5% probability.
7 0
3 years ago
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