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3 years ago

HELP ON GEOMETRY!!! PHOTO ATTACHED

Mathematics

1 answer:

Dvinal [7]3 years ago

7 0

Answer:

q = 3 units

Step-by-step explanation:

$In\: \triangle GFH \: and\; \triangle GJI\\\angle GFH \cong \angle GJI..(each\: 90\degree)\\\angle FGH \cong\angle JGH..(common\: angles)\\\therefore \triangle GFH \sim \triangle GJI..(by \: AA\: postulate)\\\\\therefore \frac{GF}{GJ}=\frac{HF}{IJ}..(By\: c.s.s.t.)\\\\\therefore \frac{4}{8}= \frac{q}{6}\\\\\therefore \frac{1}{2}= \frac{q}{6}\\\\q =\frac{6}{2}\\q= 3 \: units$

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A conveyor belt moves at a constant rate of 12 feet in 3 seconds. A second conveyor belt moves at a constant rate of 21 in 7 sec

White raven [17]

Answer:

No.

Step-by-step explanation: If we look at the first conveyor belt, the rate is 12ft in 3 seconds, or 4 feet a second. The second conveyor belt moves at 21 feet in 7 seconds, or 3 feet a second. Since the two values are unequal, we can conclude it is not a proportional relationship.

6 0

3 years ago

Nadia finds out that her favorite horse family population is increasing at a constant rate. The horse family was at 24 in 2011 a

Dahasolnce [82]

$\begin{gathered} y-24=\frac{8}{3}(x-2011) \\ \text{There will be 48 horses in 2020 (option A)} \end{gathered}$ Explanation:

The initial number of horses = 24

year = 2011

Coordinates (2011, 24)

when the number of horses became 32, year was 2014

Coordinates (2014, 32)

We find the slope = rate of change

slope = change in number of horses/change in number of years

slope = (32-24)/(2014-2011)

slope = 8/3

The point slope formula:

$\begin{gathered} y-y_1=m(x-x_1) \\ U\sin gpoint\colon x_1=2011,y_1=24 \end{gathered}$ $y-24=\frac{8}{3}(x-2011)$

The number of horses in year 2020

using points: (2011, 24) and (2020, y), we equate with the slope since it is constant for any two points on this model.

8/3 = (y - 24)/(2020 - 2011)

8/3 = (y - 24)/9

cross multiply:

8(9) = 3(y - 24)

72 = 3y - 72

72 + 72 = 3y

144 = 3y

144/3 = 3y/3

y = 48

Hence, there will be 48horses in 2020 (option A)

4 0

1 year ago

The local train heading for Westford at 60km/h and the express train heading for Eastford at 80 km/h pass each other at Centervi

Wewaii [24]

Answer:

The maximum distance to the nearest kilometer between Westford and Centerville is 111.43 km.

Step-by-step explanation:

Local train stats:

Rate = 60 km/h

Distance = x km

Time = x/60 hours

Express train stats:

Rate = 80 km/h

Distance = $(195-x)$ km

Time = $(195-x)/80$ hours

Now we will equate both the times.

$x/60 =(195-x)/80$

$x/3= (195-x)/4$

$4x= 585-3x$

$7x= 585$

x = 83.57 km

$195-x=195-83.57= 111.43$ km

Hence, the maximum distance to the nearest kilometer between Westford and Centerville is 111.43 km.

3 0

3 years ago

A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long?

ser-zykov [4K]

I believe it would be 12, I believe this because its states that it is TWICE as long therefore is made from the same metal so 6x2=12

8 0

3 years ago

Let p, q, and r represent the following statements"

Nitella [24]

In logic, own symbols are used in order to be able to represent the relations between propositions in a general and independent way to the proposition, in order to be able to find the relationship process that operates in the communicated message, the propositional logic.

For this purpose there are, among others, the following logical operators: conjunction (and) ∧, disjunction (or) ∨, denial (not) ¬, conditional (if - then) ⇒ and double conditional (if and only if, iff) ⇔.

So for this case we have:

Answer

a) Sam had pizza last night if and only if Chris finished her homework.

p⇔q

b) Pat watched the news this morning iff Sam did not have pizza last night.

r⇔¬p

c) Pat watched the news this morning if and only if Chris finished her homework and Sam did not have pizza last night.

r⇔(q∧¬p)

d) In order for Pat to watch the news this morning, it is necessary and sufficient that Sam had pizza last night and Chris finished her homework.

r⇔(p∧q)

e) q ⇔ r

Chris finished his homework if and only if Pat watched the news this morning

f) p ⇔ (q ∧ r)

Sam had pizza last night if and only if Chris finished his homework and Pat watched the news this morning

g) (¬p) ⇔ (q ∨ r)

Sam didn't have pizza last night if and only if Chris finished his homework or Pat watched the news this morning

h) r ⇔ (p ∨ q)

Pat watched the news this morning if Sam had pizza last night or Chris finished his homework

4 0

3 years ago