Answer:
see the explanation
Step-by-step explanation:
In this problem
I will assume that the total amount required for the trip is $1,200
so
Let
x ----> the number of weeks
we know that
The number of weeks multiplied by $75 plus $300 must be at least $1,200
In this context, the term "at least" means "greater than or equal to"
so
The linear inequality that represent this problem is

Solve for x
subtract 300 both sides


Divide by 75 both sides

therefore
The minimum number of weeks you need to save is 12
Answer:

Step-by-step explanation:

Let's take one of the equations and solve for x. I'll take the first one.

Divide by 13.

Now replace x in the second equation.

Distribute -8

Break down the fraction.

Subtract 

Subtract 6y

Combine like terms;

Solve;

Keep solving;

Multiply by the negative reciprocal of the fraction next to y.

On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10

After having found y, replace it in any of the equations to find x.

Answer:
Step-by-step explanation:
It says Renita takes minutes to ride half a mile.
She leaves 30 minutes before school.
Total distance is

In

Therefore total time to reach school will be 5 x 5 = 25minutes.
Since she leaves 30minutes before school. She will reach 5minutes early before school.
6/x=27
times both sides by x
6=27x
divide both sides by 27
6/27=x
2/9=x
the missing number is 2/9