Saundra room is 15 ft long by 9 feet wide. She is putting carpet in the room and cost $3.75 per square foot how many how much wi
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Answer:
Step-by-step explanation:
<h2>This is an independent event probability problem , that is the first event does not affect the occurrence of the second event.</h2>The sample space of the first die is S1= {1,2,3,4,5,6}
The sample space of the second die is S2= {1,2,3,4,5,6}
1. the probability that the first number cube shows a Four pr (4)=
2. the probability that the second number cube shows an odd number=
odd numbers in the sample space are 1,3,5= 3
pr(odd)
For the two event to happen the probability is =
Answer:
Step-by-step explanation:
The summary of the given data includes;
sample size for the first school = 42
sample size for the second school = 34
so 16 out of 42 i.e = 16 and 18 out of 34 i.e
= 18 have ear infection.
the proportion of students with ear infection Is as follows:
= 0.38095
= 0.5294
Since this is a two tailed test , the null and the alternative hypothesis can be computed as :
level of significance ∝ = 0.05,
Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.
The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.
The pooled standard error can be computed by using the formula:
The test statistics is ;
z = - 1.368
Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.
Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools