(breaths in) True, <span>The </span>point<span> at which the circle and the line intersect is the </span>point of tangency<span>.</span>
Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
4/5x + 4/3 = 2x....there are 2 ways to do this...one with fractions, one without.
with :
4/5x + 4/3 = 2x
4/3 = 2x - 4/5x
4/3 = 10/5x - 4/5x
4/3 = 6/5x
4/3 * 5/6 = x
20/18 = x
10/9 = x
without :
4/5x + 4/3 = 2x....multiply by common denominator of 15
12x + 20 = 30x
20 = 30x - 12x
20 = 18x
20/18 = x
10/9 = x
80 * 5/8 will give you how many are thoroughbreds.
80 * 5/8 = 50
Now subtract this from all of the horses.
80 - 50 = 30.
There are 30 quarter horses.
OR If 5/8 of the horses are thoroughbreds, then 3/8 are quarter horses.
80 * 3/8 = 30.
Answer:
Step-by-step explanation:
6x+9=63
6x=63-9
6x=54
x=54/6
x=9
I encourage you to figure out the justification yourself.
