Answer:
2x
Step-by-step explanation:
I think so not sure try it tho
The tangent to through (1, 1, 1) must be perpendicular to the normal vectors to the surfaces and at that point.
Let . Then is the level curve . Recall that the gradient vector is perpendicular to level curves; we have
so that the gradient of at (1, 1, 1) is
For the surface , we have
so that . We can obtain a vector normal to by taking the cross product of the partial derivatives of , and evaluating that product for :
Now take the cross product of the two normal vectors to and :
The direction of vector (24, 8, -8) is the direction of the tangent line to at (1, 1, 1). We can capture all points on the line containing this vector by scaling it by . Then adding (1, 1, 1) shifts this line to the point of tangency on . So the tangent line has equation
Answer:
ASDASD
Step-by-step explanation:
Answer:
d for sure jsjeieoeoeooeiekekejej answer is not being send because of less typing so .
Answer: 4 • (2x - 7) • (x + 3)
Step-by-step explanation:
(4x+12)(2x-7)
8x²-28x+24x-84
8x²-4x-84