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Lemur [1.5K]
2 years ago
9

I need some help so if someone could help with shown work

Mathematics
1 answer:
murzikaleks [220]2 years ago
8 0

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>

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√6·√5·√2 what is the answer for this. Im very confused
miskamm [114]

Answer:

<em>2√15 is your answer </em><em>.</em><em> </em><em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>

7 0
2 years ago
Read 2 more answers
Write an expression in factored form that is equivalent to the given expression. 1/2x + 4 . can u also tell how you solved it ?
Rufina [12.5K]
2 ways: Easy and hard
Hard=A
Easy=B
A: 1/2x+4 work from there so we do fun stuff with it make something that can be simplified so 1/2x+4 times (2/2)=x+8 now square the whole thing and put the result in a square root thingie (x+8)^2=x^2+16x+64 \sqrt{x^2+16x+64} multiply the whole thing by 4/4 and put \sqrt{16} [\tex] on top so then &#10;[tex] \sqrt{x^2+16x+64} times \frac{ \sqrt{16} }{4}=\frac{\sqrt{(16)(x^2+16x+64)}}{4}=\frac{ \sqrt{16x^2+256x+1024} }{4} to solve it, factor out the 16 in the square root and then square root 16 to get 4 then it will be (4 times square root of equation)/4=square root of equatio factor square root of equation and square root it and get x+8 divide by 2 to get 1/2x+4


B: 1/2x+4
put stuff that cancels out
1/2x+3x-3x+4+56-56
move them around
3 and 1/2x-3x+60-56
or
2x-3x+1 and 1/2x+30-20+30-36
then just add like terms to solve

5 0
3 years ago
What is the value of x in the equation 3(4x+6) =21<br> A) 1/4<br> B) 13/4<br> C) 4/13 <br> D) 12/7
nata0808 [166]
3 (4x + 6) = 21
4x + 6 = 21/3
4x + 6 = 7
4x = 7 - 6
4x = 1
x = 1/4

8 0
3 years ago
In the diagram AB=AD and
hammer [34]

Answer:

AC ≅ AE

Step-by-step explanation:

According to the SAS congruence theorem, if two triangles have 2 corresponding sides that are equal, and also have one included corresponding angle that are equal to each other in both triangles, both triangles are regarded as congruent.

Given ∆ABC and ∆ADC in the question above, we are told that segment AB ≅ AD, and also <BAC ≅ <DAC, the additional information that is necessary to prove that ∆ABC and ∆ADC are congruent, according to the SAS theorem, is segment AC ≅ segment AE.

This will satisfy the requirements of the SAS theorem for considering 2 triangles to be equal or congruent.

6 0
3 years ago
A rectangle has vertices P(-7, -5) , Q(-7, 8), R(3, 8), and S(3, -5). What is the length, in units, of RS¯¯¯¯¯¯¯? 3 units
cupoosta [38]
21 !; =47 she’d go gsmj. Fav
6 0
3 years ago
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