Step-by-step explanation:
In this case, you input the value of y (y = 6) into the equation ( 2.5(y-x)= 0)
2.5(6-x) = 0
Open the bracket,
(2.5×6)-2.5x= 0
Collect like terms.
2.5x= 2.5×6
Divide both sides by the coefficient of x (2.5)
x = 6
So,
x= 6 is true.
.
Substituting 6 for x in the equation,
2.5(6-6)= 0
2.5•0 = 0
0= 0
Which is also true.
Answer:
L = 70
W = 32
Step-by-step explanation:
P = 2L + 2W
P 204 feet
W = x
L = 2x + 6
P = 2L + 2W
P = 2*(2x + 6) + 2*x
P = 4x + 12 + 2x
P = 6x + 12
But we know that P = 204 So 6x + 12 = 204
6x + 12 = 204 Subtract 12 from both sides
6x + 12 - 12 = 204 - 12 Collect like terms on the right
6x = 192 Divide by 6
x = 192/6
x = 32
Answer
W = 32
L = 2*W + 6
L = 2*32 + 6
L = 64 + 6
L = 70
Answer:
1813.137 KJ
Step-by-step explanation:
potential energy of the body = mgH
where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m
here m= 1000 kg, g= 9.81 m/s^2 and H= 607 feet = 607×0.305= 185.135 m
hence the potential energy p= 1000×9.81×185.135= 1813137.2 J
= 1813.137 KJ
hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ
The solution to the problem is as follows:
If you use Ln you can get rid of e.
ln(e^0.4x) = ln(0.4)
0.4x = ln(0.4)
x = (ln(0.4))/0.4
<span>x = -2.29
</span>
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