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Lemur [1.5K]
3 years ago
9

I need some help so if someone could help with shown work

Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>

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The first element in an arithmetic sequence is 2. Its twenty second is 14. Find the value of n so that a(n)=6
Aleks04 [339]

Answer:

<h2>n = 8</h2>

Step-by-step explanation:

Given the nth term of an arithmetic sequence to be Tn = a+(n-1)d

a = first term of the sequence

n = number of terms

d = common difference.

Given the first element a = 2 and 22nd to be 14

T22 = a+(22-1)d = 14

a+21d = 14

Substtuting a = 2 into the equation to get d

2+21d = 14

21d = 12

d = 12/21

d = 4/7

The nth term of the sequence given a = 2 and d = 4/7 will be expressed as;

Tn = 2+(n-1)4/7

Given Tn = 6

6 = 2+(n-1)4/7

6 = 2+4/7 n - 4/7

6-2+4/7 = 4/7 n

32/7=4/7 n

32 = 4n

n = 32/4

n = 8

8 0
3 years ago
Can you help me with this please???
Dahasolnce [82]

Answer:

c?

Step-by-step explanation:


8 0
3 years ago
Yesterday , the snow was 2 feet deep in front of archies house. Today, the snow depth dropped to 1.6 feet because the day is so
olga55 [171]
Earlier snow depth = 2 feet
later snow depth = 1.6 feet

change 
2 - 1.6
0.4 feet

percentage change
(0.4 / 2) * 100
20 %
6 0
4 years ago
Read 2 more answers
A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s
Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

h(t)=-16t^2+32t+128

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

-16t^2+32t+128=0

The above is a quadratic equation. It can be solved by the formula as follows :

t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = -16, b = 32 and c = 128

t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s

Neglecting negative value, the projectile will land after 4 seconds.

4 0
3 years ago
O resultado da. Soma de (-26)com (+5) ?
zalisa [80]

Answer:

(-26) (+5)

=-+= -

it means -26-5

Answer 21

6 0
3 years ago
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