Is y=10/x linear or not

Mathematics

2 answers:

vfiekz [6]2 years ago

6 0

Answer:

Yes it goes in a straight line

Step-by-step explanation:

Sergeeva-Olga [200]2 years ago

4 0

A graph of a function y = f(x) is symmetric with respect to the origin if replacing x by -x and y by -y yields the same function. For y = 10x, if we replace x by -x and y by -y, we get -y = -10x, which simplifies to y = 10x. Thus, the graph of y = 10x is symmetric with respect to the origin.

Linear functions are odd degree functions. These type of functions do not have any symmetry with respect to the either axis.

However, the function y=mx+b

where m = ±1

b = 0

does have symmetry with respect to the origin.

You might be interested in

Let f(x)=g(x)h(x), g(10)=-4, h(10)=560, g'(10)=0, and h'(10)=35. find f'(10)

Ulleksa [173]

This question has extraneous info to trick you.
f(x) = g(x)h(x) ⇒ f'(x) = g'(x)h'(x) . Letting x = 10, we get f'(10) = g'(10)h'(10). then just plug in the values provided. g(10) and h(10) are there to throw you off, just use g'(10) and h'(10).
So f'(10), pronounced "eff prime of ten", = 0 * 35 = 0.

If the question were asking for f(10) instead of f'(10) then you would use g(10) and h(10), ⇒-4*560=90.

7 0

3 years ago

A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long

stepladder [879]

Answer: 1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀ where

a is the acceleration (in this case it is gravity)
v₀ is the initial velocity
h₀ is the initial height

Given:

a = -9.81 (if it wasn't given in your textbook, you can look it up)
v₀ = 12
h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION: 0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

a=-9.81, b=12, c=3

$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\$