Answer:
![[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]](https://tex.z-dn.net/?f=%5Bp-%7Cp%7C%2A10%5E%7B-3%7D%20%5C%2C%20%2C%20%5C%2C%20p%2B%7Cp%7C%2A%2010%5E-3%5D)
Step-by-step explanation
The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is
r = |p*-p|/|p|
we want r to be at most 10⁻³, thus
|p*-p|/|p| ≤ 10⁻³
|p*-p| ≤ |p|* 10⁻³
therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]
Answer:
8
Step-by-step explanation:
36/9=4
12-4=8
8 is your answer
Answer:
It would be great if you would provide the image itself. I will totally answer your question.
The answer is d.
First you have to divide 160/ 1/4. So you would do 160/1 divided by 1/4. Because of keep, change and flip. (k.c.f) you would keep 160/1, change the division sign, then flip 1/4 to 4/1. Then you multiply 160/1*4/1. Then you would get 640. Hope this helped.
Answer:
sqrt(35) ≈5.916079783
Step-by-step explanation:
sqrt(35)
35 = 5*7
Neither of these numbers is a perfect square so
sqrt(35) cannot be simplified
it can be approximated
sqrt(35) ≈5.916079783
