With a given parallel line and a given point on the line
we can use the point-line method: y-y0=m(x-x0)
where
y=mx+k is the given line, and
(x0,y0) is the given point.
Here
m=-10, k=-5, (x0,y0)=(-3,5)
=> the required line L is given by:
L: y-5=-10(x-(-3))
on simplification
L: y=-10x-30+5
L: y=-10x-25
Answer:
The amount of weight he has lost in 3 months is 1.215 stone or 1 stone 3 pounds
Step-by-step explanation:
From the above question, we are to calculate the amount of weight he has lost in three months
1 stone = 14 pounds
Let's convert all the weight lost to stone
At the start of the diet keirin weighted 14 stone 13 pounds
14 pounds = 1 stone
13 pounds = x
Cross Multiply
14x = 13
x = 13/14
x = 0.9285714286 stone
Approximately = 0.929 stone
Hence:
14 stone 13 pounds = 14 + 0.929 = 14.929 stone
Three months later he weighted 13 stone 10 pounds
14 pounds = 1 stone
10pounds = x
Cross Multiply
14x = 10
x = 10/14
x = 0.7142857143 stone
Approximately = 0.714 stone
Hence:
13 stone 10 pounds = 13 + 0.714 = 13.714 stone
The amount of weight he has lost is calculated as:
14.929 stone - 13.714 stone = 1.215 stone or 1 stone 3 pounds
Answer:
B.
Step-by-step explanation:
