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harina [27]
3 years ago
8

Planets are constantly moving. In fact, the name planet means wanderer. What force(s) is responsible for the constant movement o

f the planets in our solar system?
A) inertia and gravity
B) gravity only
C) inertia only
D) friction


I know its not math
Mathematics
1 answer:
Maksim231197 [3]3 years ago
3 0
Inertia and gravity
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Use the Binomial Theorem/Pascal's Triangle to expand (2a + 2b)^5
pochemuha

Answer:  

32a^5+160a^4b+320a^3b^2+320a^2b^3+160ab^4+32b^5

============================================================

Explanation:

Let's use Pascal's Triangle

In the row that starts with 1,5,... we have the values 1,5,10,10,5,1

These will be the coefficients of the terms.

Let x = 2a and y = 2b

We want to expand out (x+y)^5

Using pascals triangle, we get the following expansion

(x+y)^5 = 1x^5y^0+5x^4y^1+10x^3y^2+10x^2y^3+5x^1y^4+1x^0y^5

The numbers in bold are the coefficients 1,5,10,10,5,1 found earlier.

Note how the exponents for x start at 5 and count down to 0; while the y exponents start at 0 and count up to 5. For any term, the x and y exponents always add to 5 for the expansion of (x+y)^5. In general, the exponents of any term will add to n for (x+y)^n.

At this point, we plug in x = 2a and y = 2b

Since this will clutter things a bit, I'll do it term by term

  • 1x^5y^0 = 1(2a)^5(2b)^0 = 1(32a^5)(1) = 32a^5
  • 5x^4y^1 = 5(2a)^4(2b)^1 = 5(16a^4)(2b) = 160a^4b
  • 10x^3y^2 = 10(2a)^3(2b)^2 = 10(8a^3)(4b^2) = 320a^3b^2
  • 10x^2y^3 = 10(2a)^2(2b)^3 = 10(4a^2)(8b^3) = 320a^2b^3
  • 5x^1y^4 = 5(2a)^1(2b)^4 = 5(2a)(16b^4) = 160ab^4
  • 1x^0y^5 = 1(2a)^0(2b)^5 = 1(1)(32b^5) = 32b^5

So in the end, the expression (2a+2b)^5 expands out to

32a^5+160a^4b+320a^3b^2+320a^2b^3+160ab^4+32b^5

The binomial theorem uses the same basic idea, but instead of using Pascal's Triangle to get the coefficients, you'll use the nCr combination formula.

8 0
2 years ago
Greg started baking at 6:05 PM and finished at 7:42 PM.
FrozenT [24]

Answer:

97 minutes

Step-by-step explanation:

Starting at 6:05, it will take 55 minutes to get to 7:00. Then you can add the 42 minutes to the 55 to get a total amount. This results in 97 minutes in total for your answer.

8 0
3 years ago
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If the sun approximately 1.5 * 10/11 meters from Earth how long does it take for light to reach earth
Agata [3.3K]
The sun is 1.5*10^11 METERS from the Earth. In that case it takes approximately 8.3 minutes for sunlight to reach Earth. 
<span>t=(1.5*10^11/3.0*10^8)/60=8.33 minutes </span>
<span>If you did want a hypothetical that puts the Earth at 1.5*10^11 kilometers from the sun, then it would take 8333.3 minutes for the sunlight to reach the "Earth's" surface. </span>
<span>t=(1.5*10^14/3.0*10^8)/60=8333.3 minute</span>
4 0
3 years ago
Hello please help posted picture of question
Naddika [18.5K]
The answer is b) because if a number is to the left of a point on a line, it is less than the value of the point. If n=5, m must be less than 5
5 0
3 years ago
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Find the area under the curve y = 5/x3 from x = 1 to x = t. evaluate the area under the curve for t = 10, t = 100, and t = 1000.
frutty [35]
Is there more to this question?
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