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3 years ago

10=ax-3b solving for x

Mathematics

2 answers:

ozzi3 years ago

5 0

Answer:

$x=\frac{10+3b}{a}$

Step-by-step explanation:

The given equation is

$10=ax-3b$

We need to solve this equation for x.

Add 3b on both sides in the above equation.

$10+3b=ax-3b+3b$

$10+3b=ax$

Divide both sides by a in the above equation to isolate variable x.

$\frac{10+3b}{a}=\frac{ax}{a}$

$\frac{10+3b}{a}=x$

Interchange the sides.

$x=\frac{10+3b}{a}$

Therefore the solution of given equation is $x=\frac{10+3b}{a}$ .

RideAnS [48]3 years ago

3 0

10 = ax-3b
3b+10 = ax
(3b+10)/a = (ax)/a
x = (3b+10)/a

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Use the given inverse to solve the system of equations. left brace Start 3 By 3 Matrix 1st Row 1st Column x minus y plus z 2nd C

natka813 [3]

The interpretation of the given question is as follows:

Use the given inverse to solve the system of equations

$x- y - z = -6 \\ \\ 2y + z = -6 \\ \\ 3x -8 y = - \dfrac{1}{2}$

The inverse of $\left[\begin{array}{ccc}1&-1&1\\0&2&1\\3&-8&0\end{array}\right] is \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right]$

x =

y =

z =

Answer:

x = - 1.5

y = - 0.5

z = - 5

Step-by-step explanation:

Using the correlation of inverse of matrix AX = B to solve the question above;

AX = B

⇒ A⁻¹(AX) = A⁻¹ B

X = A⁻¹ B

So ;

X = A⁻¹ B

$\left[\begin{array}{c}x\\y\\z\end{array}\right] =$ $\left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right] =$ $\left[\begin{array}{ccc}-6\\ -6\\- \dfrac{1}{2}\end{array}\right]$

$\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(-8*-6)+(8*-6)+(3*-\dfrac{1}{2})\\(-3*-6)+(3*-6)+(1*-\dfrac{1}{2})\\(6*-6)+(5*-6)+(-2* - \dfrac{1}{2})\end{array}\right]$

$\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(48)+(-48)+(\dfrac{-3}{2})\\(18)+(-18)+(\dfrac{-1}{2})\\(-36)+(30)+(1)\end{array}\right]$