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LuckyWell [14K]
3 years ago
12

10=ax-3b solving for x

Mathematics
2 answers:
ozzi3 years ago
5 0

Answer:

x=\frac{10+3b}{a}

Step-by-step explanation:

The given equation is

10=ax-3b

We need to solve this equation for x.

Add 3b on both sides in the above equation.

10+3b=ax-3b+3b

10+3b=ax

Divide both sides by a in the above equation to isolate variable x.

\frac{10+3b}{a}=\frac{ax}{a}

\frac{10+3b}{a}=x

Interchange the sides.

x=\frac{10+3b}{a}

Therefore the solution of given equation is x=\frac{10+3b}{a}.

RideAnS [48]3 years ago
3 0
10 = ax-3b
3b+10 = ax
(3b+10)/a = (ax)/a
x = (3b+10)/a
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natka813 [3]

The interpretation of the given question is as follows:

Use the given inverse to solve the system of equations

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Step-by-step explanation:

Using the correlation  of inverse of matrix AX = B to solve the question above;

AX = B

⇒ A⁻¹(AX)  = A⁻¹ B

X =  A⁻¹ B

So ;

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\left[\begin{array}{c}x\\y\\z\end{array}\right] =     \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right] =   \left[\begin{array}{ccc}-6\\ -6\\- \dfrac{1}{2}\end{array}\right]

   

 \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(-8*-6)+(8*-6)+(3*-\dfrac{1}{2})\\(-3*-6)+(3*-6)+(1*-\dfrac{1}{2})\\(6*-6)+(5*-6)+(-2* - \dfrac{1}{2})\end{array}\right]

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(48)+(-48)+(\dfrac{-3}{2})\\(18)+(-18)+(\dfrac{-1}{2})\\(-36)+(30)+(1)\end{array}\right]

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(\dfrac{-3}{2})\\(\dfrac{-1}{2})\\(-5)\end{array}\right]

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-1.5\\-0.5\\ -5\end{array}\right]

5 0
3 years ago
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Step-by-step explanation:

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Norma-Jean [14]
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