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Travka [436]
3 years ago
6

WHEN gEORGE AND aNTHEA WERE MARRIED 120 OF THE GUEST aNTHEA'S FAMILY OR FRIENDS. THIS WAS 60 PERCENT OF THE TOTAL number of gues

t. How many guest were altogether ?
Mathematics
1 answer:
Mama L [17]3 years ago
3 0

Answer:

Step-by-step explanation:

In this problem, we will use ratios

60%------->120 guests

30%-------->60guests

10%---------->20guests

Multiply by 10 to both sides to get 200

100%--------> 200 guests

hope this helps!

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A local radio station had a contest to see who could guess closest to the actual number of jellybeans that filled a small car. t
Allushta [10]
Given:
Number of jelly beens in the car: 785,000
Number of jelly beans in a bag: 800

Number of bags needed to fill the car?

785,000 / 800 = 981.25

Randall claimed = more than 981 bags
Susie claimed = exactly 981 bags.

Randall is correct. More than 981 bags.

981 x 800 = 784,800  

There is a missing 200 jelly beans if exactly 981 bags were used. Thus, a quarter of the 982nd bag is used to complete the 785,000 jelly beans. 
4 0
3 years ago
What percent of 21 is 105? ​
Natasha_Volkova [10]

Answer:

20%

Step-by-step explanation:

21/ 105

= 0.2 x 100

20%

6 0
3 years ago
Read 2 more answers
Find the 7th term of a geometric sequence with t1=5 and r = -2.
Shtirlitz [24]
An=Asub1(r)n-¹
=5(-2)7-¹
=5(64)
A7=320
4 0
3 years ago
Consider the line y=1 x -1 and the point P=(2,0).
Montano1993 [528]

Answer:

Step-by-step explanation:

d(x)=√((x-2)2+(y-0)²)

=√((x-2)²+y²)

=√((x-2)²+(x-1)²)

=√(x²-4x+4+x²-2x+1)

=√(2x²-6x+5)

D=d²(x)=2x²-6x+5

b.\\\frac{dD}{dx}=4x-6\\\frac{dD}{dx}=0,gives \\4x-6=0\\x=\frac{3}{2}\\\frac{d^2D}{dx^2}=4 >0 at x=\frac{3}{2}\\so~D~or~d^2~or~d~is~minimum~at~x=\frac{3}{2}\\so~y=1(\frac{3}{2} )-1=1/2=0.5\\so~nearest~point~is~(1.5,0.5)

8 0
3 years ago
The length of a rectangle is 3 centimeters less than four times its width. Its area is 10 square centimeters. Find the dimension
Kay [80]

Answer:

W = 2 cm

L = 5 cm

Step-by-step explanation:

A rectangle is a four sided shape with 4 perpendicular angles. It has two pairs of parallel sides which are equal in distance: width and length. Its area, the amount of space inside it, can be found using the formula A = l*w. If the area is 10 cm² and the length is "3 cm less than 4 times the width" or 4w - 3, you can substitute and solve for w.

A = l*w

10 = (4w - 3)(w)

10 = 4w² - 3w

Subtract 10 from both sides to make the equation equal to 0. Then solve the quadratic by quadratic formula.

4w² - 3w - 10 = 0

Substitute a = 4, b = -3 and c = -10.

w = \frac{3 +/- \sqrt{(-3)^2 - 4(4)(-10)} }{2(4)} = \frac{3 +/- \sqrt{9 +160)} }{8} =  \frac{3 +/- \sqrt{169} }{8} = \frac{3+/-13}{8}

There are two possible solutions which can be found.

3 + 13 / 8 = 16/ 8 = 2

3 - 13 / 8 = -10/8 = -5/4

Since w is a side length or distance, it must be positive so w = 2 cm.

If the width is 2 cm then the length is 4(2) - 3 = 8 - 3 = 5 cm.

8 0
3 years ago
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