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AlexFokin [52]
3 years ago
13

What is the quadratic formula

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

x = -b +or- the square root of (b^2-4ac) ALL / 2a

sing to "pop goes the weasel" lol

kodGreya [7K]3 years ago
6 0

Answer: A

Step-by-step explanation:

The quadratic formula is x = -b ± √b^2 - 4ac divided by 2a. I can't write it down using text but I hope this helps.

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Stacy finds a shirt that costs $43.00 on sale for 30% off the regular price. How much will the shirt cost before tax?
yan [13]

Answer:

60

Step-by-step explanation:

7 0
3 years ago
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Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the
mestny [16]

Answer:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

Step-by-step explanation:

Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

Determine the equivalent expression

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Simplify the first fraction

\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}

\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}

Apply law of indices:

5q^5w^4*4\left(q^6\right)^2 * w^{5}

Evaluate the bracket

5q^5w^4*4 * q^{12} * w^{5}

Collect Like Terms

5*4q^5* q^{12}*w^4  * w^{5}

20q^5* q^{12}*w^4  * w^{5}

20q^{5+12}*w^{4+5}

20q^{17}w^9

Hence:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

7 0
3 years ago
Seth is using the figure shown below to prove the Pythagorean Theorem using triangle similarity:
Damm [24]

Part A: A pair of similar triangles is triangle DEF and triangle GFD.

Part B: Traingle DEF ~ triangle GFD by the AA Similarity Theorem

Part C: By applying the Leg Rule, the length of segment ED = 4 units.

<em><u>Recall:</u></em>

  • Based on the Angle-Angle Similarity Theorem (AA) two triangles that have two pairs of congruent triangles can be proven to be similar to each other.
  • In a right triangle where the altitude intersects the hypotenuse, the Leg Rule applies, which is: Hypotenuse/Leg = Leg/Part

The Figure of the given triangle DEF is shown in the attachment below.

<em><u>Part A: A Pair of Similar Triangles</u></em>

A pair of similar triangles are traingle DEF and triangle GDF

<em><u>Part B: Reason for Similarity</u></em>

Triangle DEF and GDF have two pairs of congruent angles, ∠EDF ≅∠DGF and ∠EFD ≅∠GFD.

  • Therefore, based on the AA Similarity Theorem, Traingle DEF ~ Triangle GDF.

<em><u>Part C: Length of Segment ED</u></em>

Given the following,

  • EF = 8 (Hypotenuse)
  • EG = 2 (Part)
  • ED = ? (Leg)

Thus:

8/ED = ED/2 (Leg Rule)

  • Cross multiply

ED² = (8)(2)

ED² = 16

  • Find the square root of both sides

ED = 4

Learn more about AA Similarity Theorem on:

brainly.com/question/24147586

5 0
3 years ago
-15 +n=-9<br> Help!!!!!!!!!
s344n2d4d5 [400]
N would be 6 for this one
5 0
3 years ago
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Help me please this is due today
matrenka [14]

Answer:

LCM = 20, GCF = 9

Step-by-step explanation:

4 0
3 years ago
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