5x-29>-34
5x>-5
x>-1
x<1
2x+31<29
2x<-2
x<-1
x>1
Answer:
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Step-by-step explanation:
Given data
mean = 5.1 millimeters (mm)
standard deviation = 0.7 mm
to find out
percent (%) of ancient prehistoric thinner than 3
solution
we have given mean and SD
so Z will be = x -mean / SD
Z = ( x - 5.1 ) / 0.7
so P( x < 3 ) = P ( (x - 5.1 ) / 0.7 < ( 3 - 5.1 ) / 0.7 )
P( Z = ( 3 - 5.1 ) / 1.5 )
P( Z = -3 ) = 0.0013
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Answer:
5:00 pm
Step-by-step explanation:
Let
x -----> the umber of hours
y ----> the total distance in miles
we know that
The distance is equal to the speed multiplied by the time
Find out the distance traveled by Ariel at 11:00 am
11:00 am-09:00 am=2 hours
45(2)=90 miles
so
<em>Ariel's linear equation is</em>
----> equation A
<em>Ariel's brother linear equation is</em>
----> equation B
Equate equation A and equation B

Solve for x



Adds 11:00 am + 6 hours=17:00 =5:00 pm
Answer: Choice B) -4
The lower quartile, also known as Q1 or the first quartile, is the left edge of the box. In this case, that is at -4. We can drop a vertical line from the left edge of the box until we hit -4 on the number line.
Side Note: 25% of the data values are below Q1, while 75% of the data values are above Q1