Answer:
5.444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444
Step-by-step explanation:
4 is infinite
Step-by-step explanation:
√12=
2√3
÷2. ÷2
√3. 1.8
√3≈1.7
1.7<1.8
3.6>√12
method 2
(3.6)^2>12
There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
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C(n,k) = n!/(k!(n-k)!)
Answer:
-262
Step-by-step explanation:
Evaluate Subtraction & Addition from right to left [or left to right, as long as you know what you are doing]:
38 + 16 - 12 - 2 - 302
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Answer:
x=10.82
Step-by-step explanation:
6^2+9^2=c^2
so
36+81=c^2
117=c^2
117/2=10.82
