A line that is parallel to y = 3, a horizontal line, would also be a horizontal line.
The only option that is a horizontal line passing through (0,6) is y = 6.
LETTER D
Answer: f(a-2) = 2a² - 14a + 28
Step-by-step explanation:
f(x) = 2x² - 6x + 8
you can take a-2 and substitute it for each x, which would look like this:
f(a-2) = 2(a-2)² - 6(a-2) + 8
then distribute those in ( )
f(a-2) = 2a² - 8a + 8 - 6a + 12 + 8
combine like terms
f(a-2) = 2a² - 14a + 28