
You wan't to get it into a format of (x+a)(x+b)=0
where a+b = 3 (the one from the 3x)
and where a*b= -4 (from the last -4)
(x+4)(x-1)=0
See how 4+(-1) = 3 and (4)(-1) = -4
now find what values of x would make the equation equal 0
x=-4
(-4+4)(-4-1) = (0)(-5) = 0
x=1
(1+4)(1-1) = (5)(0) = 0
Answer:
850 but im not sure lol
Step-by-step explanation:
645 + 225 = 870
1,320 - 870 = 450
450 + 350 = 800
800 + 50 = 850
Step-by-step explanation:
f(x) = 4x² + 7x - 18
f(-9) = 4 * (-9)² + 7 * (-9) - 18
= 324 - 63 - 18
= 243
Hope it will help :)
Answer:

Step-by-step explanation:
Given

Required
Solve for x

Change base of 16 and base of 4 to base 2

Express 16 and 4 as 2^4 and 2^2 respectively

The above can be rewritten as:


So, we have:


Multiply through by 4



Divide through by 7


Apply the following law of logarithm:
<em>If </em>
<em> </em><em>Then </em>
<em></em>
So, we have:

